The options are available for storing backups, physically are:
- In both on site and off site,, a person can backup data to a given system that is located on-site, or the backups can be sent to any remote system that is off-site.
<h3>What is a backup?</h3>
This is known to be a device that helps to save information or data temporarily or permanently.
Note that in the above, The options are available for storing backups, physically are:
- In both on site and off site,, a person can backup data to a given system that is located on-site, or the backups can be sent to any remote system that is off-site.
Learn more about backups from
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I would say the best clear answer is D, because A is a little bit unclear but I would say the best answer is D.
Why?
Mesh Topology is expensive considering more links as compared to Ring topology.
Answer:
import random
def simulate_observations():
#this generates an array of 7 numbers
#between 0 and 99 and returns the array
observations = random.sample(range(0, 100), 7)
return observations
#here,we call the function created above and print it
test_array = simulate_observations()
print(str(test_array))
Answer:
- import java.util.Scanner;
- public class num8 {
- public static void main(String[] args) {
- int first, second, third, fourth,total;
- double decimalOne, decimalTwo, decimalTotal;
- }
- public static void getData(int first, int second, int third, int fourth, double decimalOne, double decimalTwo){
- System.out.println("Enter the Values");
- Scanner in = new Scanner(System.in);
- first=in.nextInt();
- second=in.nextInt();
- third=in.nextInt();
- fourth=in.nextInt();
- decimalOne = in.nextDouble();
- decimalTwo = in.nextDouble();
- }
- public static int computeTotal(int first, int second, int third){
- return first+second+third;
- }
- public static int computeTotal(int first, int second, int third, int fourth){
- return first+second+third+fourth;
- }
- public static double computeTotal(double decimalOne, double decimalTwo){
- return decimalOne+decimalTwo;
- }
- public static void printAll( int first, int second, int third){
- System.out.println("Number one, two and three are: "+first+" "+second+" "+third);
- }
- public static void printAll( int first, int second, int third, int fourth){
- System.out.println("Number one, two and three and four are: "+first+" "+second+
- " "+third+" "+fourth);
- }
- public static void printAll( int first, int second, int third, int fourth, int fifth){
- System.out.println("Number one, two and three and four are: "+first+" "+second+
- " "+third+" "+fourth+" "+fifth);
- }
- public static void printAll( double first, double second, double third){
- System.out.println("Number one, two and three and four are: "+first+" "+second+
- " "+third);
- }
- }
Explanation:
This solution is provided in Java:
All the variable declarations are done in the main method (lines 3-6)
Eight methods as specified in the question are created (Lines 7, 17, 20, 23, 26, 29, 33 and 37).
Observe the concept of Method Overloading (i.e. methods with same name and return types but different parameter list)
Answer:
Option 1: May crash at runtime because it can input more elements than the array can hold
Explanation:
Given the code as follows:
- int[] a = {1, 3, 7, 0, 0, 0};
- int size = 3, capacity = 6;
- int value = cin.nextInt();
- while (value > 0)
- {
- a[size] = value;
- size++;
- value = cin.nextInt();
- }
From the code above, we know the <em>a</em> is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.
However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable <em>value</em> is always above zero, the while loop will persist. This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.
