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asambeis [7]
3 years ago
6

Which equation is equivalent to the equation 3x - 12 = 24?

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

C

Step-by-step explanation:

To simplify the equation, all you need to do is add 12 to both sides to cancel out the -12.

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Compare the fractions using &gt;, &lt; or=.<br> 9/10 and 78/100
kicyunya [14]

Answer:

9/10 > 78/100

Step-by-step explanation:

We can make 9/10 into 90/100, and since they now have the same denominator (Bottom number in fraction), we can now compare the numerators (Top number in fraction). 90 is greater than 78 so we can say that 9/10 > 78/100 (9/10 is greater than 78/100).

4 0
3 years ago
What is the scale factor between shape A and shape B
amid [387]
Cant see the other shape... but make a ratio using a side that is alike to both triangles... 
3 0
3 years ago
Simplify: (-2x - 3) – (3x2 – 8x + 9). Choose the standard form of the answer.
lawyer [7]

Answer:

C

Step-by-step explanation:

Given

(- 2x - 3) - (3x² - 8x + 9) ← distribute parenthesis

= - 2x - 3 - 3x² + 8x - 9 ← collect like terms

= - 3x² + 6x - 12 → C

7 0
2 years ago
A shop recorded total sales of $2,000 on Monday. On Tuesday, its sales fell by 10%. On Wednesday, sales fell by another 20% comp
GenaCL600 [577]
The shop had $2,000 in sales on Monday. 
If it fell by 10% on Tuesday, then 2000 * 0.10 equals the percentage it dropped, so it dropped by $200. So they only had $1,800 in sales on Tues. 
If they fell by another 20% on Wednesday, 1,800 * 0.20 equals a $360 drop. Now we're at $1,440. 
The sales then increased by 25% of Monday's total # of sales. 25% of Monday's sales is 2,000 * 0.25 which equals a $500 increase. Now we're at $1,940. 
Now that we're done with everything, how far are we from the beginning? That's the net change. :) We began at $2,000 on Monday, and ended with $1,940 on Thursday. 2000 - 1940 is 60, so 60 = your net change. 

TLDR: Sold $2,000 on Mon, sold $1,800 on Tues, sold $1,440 on Wed, and then sold $1,940 on Thurs. The net change is $60.
7 0
3 years ago
Problem 10-9 A sample of 40 observations is taken from a population of unknown mean wherein the standard deviation is assumed to
Svetradugi [14.3K]

Answer: (36.7, 39.3)

Step-by-step explanation:

Confidence interval for population mean:

\overline{x}\pm z^c\dfrac{\sigma}{\sqrt{n}} , where n= sample size, \overline{x}= sample mean, \sigma = population standard deviation, z^c = critical z value.

Given: n= 40 , \sigma=5\ g,\ \ \ \overline{x} = 38.0\ g

Critical z-value for 90% confidence = 1.645

Then, required confidence interval:

38.0\pm(1.645)\dfrac{5}{\sqrt{40}}\\\\= 38.0\pm (1.645)(0.79057)\\\\\approx38.0\pm1.30\\\\= (38-1.30,\ 38+1.30)=(36.7,\ 39.3)

Hence, a 90% Confidence Interval =  (36.7, 39.3)

5 0
3 years ago
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