<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,

0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Answer:
33/4 or 8 1/4
Step-by-step explanation:
-3 2/3 • (-2 1/4)
Step 1. Convert each into improper fractions
(Reply for details)
-11/3 • (-9/4)
Step 2. Multiply
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99/12
Step 3. Simplify
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33/4 or 8 1/4
Answer:
f - 4(g^7)
It's simple algebraic operations!
Answer:
3inches each month or 36inches in a year
Step-by-step explanation: