Answer:
(1) ΔMAN ≅ ΔBOY
(2) ΔMAT ≅ ΔRUG
(3) ΔEBN ≅ ΔUHR
(4) ΔTOP ≅ ΔLID
(5) ΔCAT ≅ ΔDOG
(6) ΔITP ≅ ΔLOH
Step-by-step explanation:
The following combinations of the congruent triangle facts will be sufficient to prove triangles congruent.
The combinations are:
(1) SSS (side-side-side) : If three sides of a triangle are congruent to three sides of another triangle then the triangles are congruent.
(2) SAS (side-angle-side) : If two sides and included angle of a triangle are congruent to another triangle then the triangles are congruent.
(3) ASA (angle-side-angle) : If two angles and included side of a triangle are congruent to another triangle then the triangles are congruent.
(4) RHS (right angle-hypotenuse-side) : If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent.
Part (1):
As we are given two triangles.
Side AM = Side OB
Side MN = Side BY
Side AN = Side OY
That means,
ΔMAN ≅ ΔBOY
Part (2):
As we are given two triangles.
Side MA = Side RU
Side MT = Side RG
Side AT = Side UG
That means,
ΔMAT ≅ ΔRUG
Part (3):
As we are given two triangles.
Side EB = Side UH
Side BN = Side HR
Side NE = Side RU
That means,
ΔEBN ≅ ΔUHR
Part (4):
As we are given two triangles.
Side OT = Side IL
Side OP = Side ID
Side PT = Side DL
That means,
ΔTOP ≅ ΔLID
Part (5):
As we are given two triangles.
Side AC = Side OD
Side AT = Side OG
Side TC = Side GD
That means,
ΔCAT ≅ ΔDOG
Part (6):
As we are given two triangles.
Side TP = Side OH
Side IT = Side LO
Side IP = Side LH
That means,
ΔITP ≅ ΔLOH
Since they are alternate interior angles, x+25=85.
x+25=85
x=60
x is 60 degrees.
Answer:
32 cm
Step-by-step explanation:
Add 12+5+5+4+6 to get the perimeter.
<span>1) Expression given: 20a+15ab+24b
</span>
2) Greates common factor GFC:
i) Coefficients:
20 = 2² × 5 × 1
15 = 3 × 5 × 1
24 = 2³ × 8 × 1
GCF = common numbers raised to the lower power = 1.
<span /><span /><span />
ii) Letters:
a
ab
b
Since, none letter is in the three terms, then there is not common letter as GFC.
iii) Conclusion the GCF is 1.
<span>
3) Let's see every option of the list:
</span><span>
</span><span>
</span><span>i) The factors common to 20a and 15ab are 1, 5, a, and b.
</span>
FALSE: becasue b is not in 20a.
<span /><span /><span>
ii) The factors common to 20a and 15ab are 1, 5, and a.
</span>
TRUE: 1, 5, and a are in contained in both terms.
<span /><span /><span>
</span><span>iii) The factors common to 15ab and 24b are 1, 3, a, and b.
</span>
FALSE: a is not in 24b
<span /><span /><span>
iv) The factors common to 15ab and 24b are 1, 3, and b.
</span>
TRUE: 1, 3, and b are contained in both terms.
<span /><span /><span>
v) The factors common to 20a and 24b are 1, 2, 4, a, and b.
</span>
FALSE: a is not in 24b and b is not in 20a.
<span /><span /><span>
</span><span>vi) The factors common to 20a and 24b are 1, 2, and 4.
</span>
TRUE: 1, 2, and 4 are contained in both terms.
<span /><span /><span>
vii) The GCF of the expression is ab.
</span>
FALSE: as seen above ab is not a common factor.
<span /><span /><span>
viii) The GCF of the expression is 1
</span>
TRUE: it was proved above.
<span />
Answer:
Step-by-step explanation:
C:27
Plzz give me brainliest
