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3 years ago

Find the ratio of 4 meter to 50 centimetre

1 answer:

4 0

(4 meters) / (50 centimeters)

= (4 x 100 centimeters) / (50 centimeters)

= (400 centimeters) / (50 centimeters)

= (400) / (50)

= 8 .

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Three cards are drawn from a standard deck. What is the probability that all three are hearts, given that at least two of them a

bogdanovich [222]

Answer:

1/3 I believe because we already know 2 of them are hearts

Step-by-step explanation:

3 0

3 years ago

quester [9]

Answer:

8 cm

Step-by-step explanation:

Set inequality as per question:

2000 ≤ V ≤ 2500

We know that:

V = πr²h
h = 10 cm
π = 3.14

Substitute and solve for r:

2000 ≤ 3.14*10r² ≤ 2500
2000 / 31.4 ≤ r² ≤ 2500 / 31.4
63.69 ≤ r² ≤ 79.62
64 ≤ r² < 81
r² = 64 ⇒ r = 8 cm is the possible radius

7 0

2 years ago

What are all the powers of 4 in the range 4 through 1,000

Pachacha [2.7K]

Answer:

Powers are : 4, 16 64 and 256

and this question type of question was answered from another brainly user as well lol

5 0

3 years ago

What is 1000×2000×3000×4000×5000

Sophie [7]

Answer:

120000000000000000

Step-by-step explanation:

1.2*10^17

6 0

2 years ago

Read 2 more answers

Solve: (-5/6) × (9/20) + (-5/6) × 7/25 = ?

jonny [76]

$\bf \underline{★ How \:to\: do -} \\$

Here, we are given with four fractions to multiply two of them and to add two of them. If we add them directly by taking the LCM and adding them is not a similar way. We can clearly observe that in those four fractions, we have two fractions as common i.e, we have two fractions as same. If we have two fractions or numbers as same, we can solve the sum by an other concept called as distributive property. In this property, we multiply the common fraction with the sum of other two fractions. This concept can also be done with fractions as well as integers. So, let's solve!!

$\:$

$\bf \underline{➤ Solution-} \\$

${\tt \leadsto \dfrac{(-5)}{6} \times \dfrac{9}{20} + \dfrac{(-5)}{6} + \dfrac{7}{25}}$

Group the non-common fractions in bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9}{20} + \dfrac{7}{25} \bigg)}$

First we should solve the numbers in bracket.

LCM of 20 and 25 is 100.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9 \times 5}{20 \times 5} + \dfrac{7 \times 4}{25 \times 4} \bigg)}$

Multiply the numerators and denominators in the bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45}{100} + \dfrac{28}{100} \bigg)}$

Now, write both numerators in bracket with a common denominator.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45 + 28}{100} \bigg)}$

Now, add the numerators in bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{73}{100} \bigg)}$

Write the numerator and denominator in lowest form by cancellation method.

${\tt \leadsto \dfrac{\cancel{(-5)} \times 73}{6 \times \cancel{100}} = \dfrac{(-1) \times 73}{6 \times 20}}$

Now, multiply the numerators and denominators.

${\tt \leadsto \dfrac{(-73)}{120}}$

$\:$

${\red{\underline{\boxed{\bf So, \: the \: answer \: obtained \: is \: \: \dfrac{(-73)}{120}}}}}$

3 0

3 years ago