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vazorg [7]
3 years ago
12

To keep the image in proportion what do you have to do?

Mathematics
1 answer:
hoa [83]3 years ago
5 0

Answer:

Press shift while you drag a corner handle to prevent stretching and keep your picture in proportion. Don't drag from any of the side handles; this will distort the picture even if you do press Shift!

Step-by-step explanation:

You might be interested in
The question is:
Naddik [55]

Answer:

2.5 gallons of the 20% solution must be replaced by the 36% solution.

Step-by-step explanation:

.12(20 - x) + .36x = 20(.15)

2.4 - .12x + .36x = 3

2.4 - .24x = 3

- .24x =  - .6

.24x = .6

x = 2.5

7 0
1 year ago
Raj studied for4/7of an hour,while ram studied for 5/8 of an hour.who studied for longer time
Ksivusya [100]

Answer:

Ram studied for longer time

Step-by-step explanation:

An hour = 60 minutes

Raj studied for 4/7 of an hour

= 4/7 of 60 minutes

= 4/7 × 60

= (4×60)/7

= 240/7

= 24.29 minutes

ram studied for 5/8 of an hour

= 5/8 of 60 minutes

= 5/8 × 60

= (5×60)/8

= 300/8

= 37.5 minutes

who studied for longer time?

Ram - Raj

= 37.5 - 24.29

= 13.21 minutes

Ram studied for longer time

Ram studied 13.21 minutes longer than Raj

5 0
3 years ago
Can someone help me solve this pleaaaaaaaaaaaaaaaaaase 20 points !
harkovskaia [24]
I think the answer is 220
3 0
3 years ago
Read 2 more answers
Evaluate the function at the indicated values if possible. If an indicated value is not in the​ domain, say so.
goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

\frac{(-7)+7}{(-7)^2-9}

\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0
3 years ago
Find cos theta if sin theta = 2/3. assume the terminal side of the angel falls in quadrant 2
kow [346]
Well knowing that the terminal arm of the standard position angle is in quadrant 2, we can determine the reference angle, in quadrant 2, by simply taking the difference between 180 and whatever the angle is.

So ø reference = 180 - ø in standard position.

Regardless, the reference angle is in quadrant 2, we need to then label the sides of the reference triangle based on the opposite and hypotenuse.

Solve for adjacent side using Pythagoras theorem.

A^2 = C^2 - B^2
A^2 = 3^2 - 2^2
A^2 = 9 - 4
A^2 =5
A = sq root of 5.

Then write the cos ratio using the new side.

Cos ø =✔️5/3. Place a negative in front of cos ø as cos is negative in second quadrant.
3 0
2 years ago
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