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kodGreya [7K]
2 years ago
15

sonja and jake just got married. they received $4500 in gift money and deposited it into a savings account that pays %2.85 simpl

e interest. how much will they have in savings after 3 years?
Mathematics
1 answer:
gladu [14]2 years ago
4 0

9514 1404 393

Answer:

  $4884.75

Step-by-step explanation:

The amount in a simple interest account is given by the formula ...

  A = P(1 +rt)

Here, we have principal P=$4500, interest rate r=0.0285, and time t=3. Then the amount in the savings account will be ...

  A = $4500(1 +.0285·3) = $4500·1.0855 = $4884.75

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andrew11 [14]

Answer:

11

Step-by-step explanation:

44 divided by 4=11

55 divided by 5=11

I am an expert

5 0
3 years ago
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For parties of six or more, a restaurant adds a 20% gratuity (or tip). If a
adelina 88 [10]

Answer: tThe total dinner bill with  tip = $177.90

Step-by-step explanation:

Given: Dinner bill = $148.25

Tip percent = 20%= 0.20

Total dinner bill = Dinner bill + Tip percent × (Dinner bill)

Total dinner bill = $ (148.25+0.20×148.25)

Total dinner bill = $ (148.25(1.20))

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Hence, the total dinner bill with  tip = $177.90

6 0
2 years ago
The value of 2 in 204.75 is how many times greater than the 2 in 103.52
Mariana [72]
The value is 200. It is 4 times greater
7 0
3 years ago
chegg Y=4X−2 XX has a PDF of f_X(x)=\begin{cases} 3e^{-3x} &amp; 0 \leq x \\ 0 &amp; \text{otherwise}\end{cases}f X ​ (x)={ 3e −
Licemer1 [7]

\Bbb E[Y^2] = \Bbb E[(4X - 2)^2]

so by definition of expectation,

\Bbb E[Y^2] = \displaystyle \int_{-\infty}^\infty (4x-2)^2 f_X(x) \, dx = \int_0^\infty 3(4x-2)^2 e^{-3x} \, dx

Integrate by parts (twice).

\displaystyle \int_a^b u\,dv = uv\bigg|_a^b - \int_a^b v\,du

First, let

u = (4x-2)^2 \implies du = 8(4x-2)\,dx \\\\ dv = 3e^{-3x} \, dx \implies v = -e^{-3x}

so that

\displaystyle \Bbb E[Y^2] = -(4x-2)^2 e^{-3x} \bigg|_{x=0}^{x\to\infty} + 8 \int_0^\infty (4x-2) e^{-3x} \, dx \\\\ ~~~~ = 4 + 8 \int_0^\infty (4x-2) e^{-3x} \, dx

Next,

u = 4x-2 \implies du = 4\,dx \\\\ dv = e^{-3x} \, dx \implies v = -\dfrac13 e^{-3x}

so that

\displaystyle \Bbb E[Y^2] = 4 + 8 \left(-\frac13 (4x-2) e^{-3x} \bigg|_{x=0}^{x\to\infty} + \frac43 \int_0^\infty e^{-3x} \, dx\right) \\\\ ~~~~ = 4 + 8 \left(-\frac23 - \frac49 e^{-3x}\bigg|_{x=0}^{x\to\infty}\right) \\\\ ~~~~ = 4 - \frac{16}3 + \frac{32}9 = \boxed{\frac{20}9}

7 0
1 year ago
Solve the system of equations by substitution.<br> y = 8<br> X – 2y + 3z = 3<br> 3x + 3y – 2z = 15
Dafna1 [17]

Answer:

Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down

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we will reduce the system down to one with two variables (usually by addition),

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To reduce from three variables down to two it is very important to keep the work

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This new equation we will call (A). Then we will use a different pair of equations

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with the same two variables that we can solve using either method. This is shown

in the following examples.

Example 1.

3x +2y − z = − 1

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5x +2y − z = 3

Step-by-step explanation:

6 0
3 years ago
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