3 years ago

Please please help me out ASAP

Mathematics

1 answer:

likoan [24]3 years ago

4 0

The answer are c. x=-1 and e.x=1

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What multiplies to -26 and adds to 5

Kryger [21]

The two numbers are (5+ √(129))/2 and (5-√(129))/2.

(5+ √(129))/2+ (5-√(129))/2= 5
(5+ √(129))/2* (5-√(129))/2= -26

Hope this helps~

6 0

3 years ago

Which of the following expressions is this one equivalent to?

padilas [110]

Hello from MrBillDoesMath!

Answer:

Choice D, x-2

Discussion:

Observe the the highest order term in the numerator is x^4 and the highest order term in the denominator is x^3. So the highest order term in their quotient is x^4/x^3 = x. Choice D is the only possible answer as all other choices start with x^2

Regards,

MrB

6 0

3 years ago

The answer options are

babymother [125]

Ansgilcx dhsvguydfsjhujvcouwaihgraeuvyjsghdnvufyiekghabsuivkjkesd

Step-by-step explanation:

3 0

3 years ago

Find the slope for each of the order pair. (-2,-1) and (8,-3)

kondaur [170]

Answer:

-0.2

Step-by-step explanation:

Slope (m) =ΔY/ΔX= 8-(-2)/-3-(-1)

= -1/5

= -0.2

4 0

3 years ago

Sin tita= 0.6892.find the value Of tita correct to two decimal places<br><br>

Anvisha [2.4K]

Answer:

$\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}$

$\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}$

Considering $\theta \in (0, 2\pi]$

$\theta \approx 2.38$

$\theta \approx 0.76$

Step-by-step explanation:

$\sin(\theta)=0.6892$

We have:

$\sin (x)=a \Longrightarrow x=\arcsin (a)+2\pi n \text{ or } x=\pi -\arcsin (a)+2\pi n \text{ as } n\in \mathbb{Z}$

Therefore,

$\theta= \arcsin (0.6892)+2\pi n, \quad n \in \mathbb{Z}$

$\theta = \pi -\arcsin (0.6892)+2\pi n, \quad n\in \mathbb{Z}$

---------------------------------

$\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}$

$\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}$

4 0

3 years ago