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3 years ago

Find the point(s) in which f(x)=e^5-2x and y=6 intercept

Mathematics

1 answer:

Nana76 [90]3 years ago

7 0

Answer:

(1.6, 6)

Step-by-step explanation:

$ln({e}^{5 - 2x} = 6)$

$5 - 2x = ln(6)$

$2x = 5 - ln(6)$

$x = \frac{5 - ln(6) }{2}$

y = 6

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What is the simplified form of this expression?

Rasek [7]

Answer:

B. -7 $x^{2}$ + 3x + 5

Step-by-step explanation:

(-3 $x^{2}$ + x + 5) - (4 $x^{2}$ - 2x)

-3 $x^{2}$ + x + 5 - 4 $x^{2}$ - 2x

Combine like terms

-3 $x^{2}$ - 4 $x^{2}$ = -7 $x^{2}$

x - -2x = x + 2x = 3x

-7 $x^{2}$ + 3x + 5

I hope this helps :))

3 0

3 years ago

Which number is an irrational number

iragen [17]

Square root of 15 because you don't know what know is going to go after it, unlike the others where you can guess the numbers that goes after it

7 0

3 years ago

Read 2 more answers

When solving a 2 step inequality, when do you flip the inequality sign, i keep getting these questions wrong, pls help, i mark b

vaieri [72.5K]

You flip the signs when you are dividing by a negative value.
-2x+3>15
-2x>15-3
-2x>12
x<12/-2
x<-6
Now to test this
Try putting x in the original equation when it is -5.
-2(-5)+3>15
10+3>15
13>15
This is false because our answer says x is less than -6.
Now any value less than -6 will work so let's go with -7.
-2(-7)+3>15
14+3>15
17>15
This result is True.
Hope this helps out!

3 0

3 years ago

What is the distance between the lines y = 2x and y = 2x+5? Round your answer to the nearest tenth.

Ilia_Sergeevich [38]

The distance between both lines is 2.24 units

Step-by-step explanation:

There is no straight method to find the distance between two lines. The distance can be found out by finding a point on one line and then finding the distance of that point from the other line. The y-coordinate of point is obtained by putting any value of x in equation . The x and y combined give us the point.

Given

$y=2x\\Putting\ x=1\\y=2(1)\\y=2\\So, the\ point\ on\ y=2x\ is\ (1,2)$

We have to find the distance of this point from y=2x+5

$y=2x+5\\Subtracting\ y\ from\ both\ sides\\y-y=2x+5-y\\2x-y+5=0$

The formula for finding distance of a point (x,y) from a line is:

$d=\frac{|Ax+By+C|}{\sqrt{A^2+B^2}}$

A=2

B=-1

C=5

Putting the values in the formula

$d=\frac{|(2)(1)+(-1)(2)+5|}{\sqrt{(2)^2+(-1)^2}}\\d=\frac{|2-2+5|}{\sqrt{4+1}}\\d=\frac{|5|}{\sqrt{5}}\\d=\frac{5}{\sqrt{5}}\\d=2.236\ units$

Rounding off will give: 2.24 units

The distance between both lines is 2.24 units

Keywords: Equations of lines

Learn more about distance in lines at:

#LearnwithBrainly

7 0

3 years ago

Two of the statements are true; one is a lie.

Temka [501]

Answer:

Statement 3

Step-by-step explanation:

∠GAF ≅ ∠TAE

Since, there is no relation between these angles,

Therefore, statement is False.

∠TAE and ∠FAH are complementary.

If the sum of the two angles is 90°, pair of angles is said to be complimentary angles.

Therefore, this statement is False.

∠TAF is obtuse.

Measure of obtuse angle is more than 90°

From the given picture, measure of ∠TAF = m∠TAH + m∠HAF

= 90° + 50°

= 140°

Here, m∠TAF > 90°

Therefore, ∠TAF is an obtuse angle.

Statement (3) is the correct statement.

8 0

3 years ago