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2 years ago

This makes no sense, I don’t understand

Mathematics

1 answer:

julsineya [31]2 years ago

8 0

Answer:

the range where we see the function is between x=0 and x=7

its B

A is impossible btw, no number is smaller or equal to 0 AND bigger or equal to 7

please brainliest

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Type the correct answer in each box.

Vikki [24]

Answer:

Cos<42 sin<16 :)

Step-by-step explanation:

3 0

2 years ago

Solve the problem,

Keith_Richards [23]

Answer:

24 boxes, 1 chocolate remaining

Step-by-step explanation:

289 chocolates total, each box is 12.

just divide it and whatever is left will be your remainder.

289/12 = 24 boxes, 1 chocolate remaining

sub to gauthmath sub reddit for more help like this !

3 0

3 years ago

Order the following numbers from least to greatest. -14 1/5,<br> -14.04,<br> -14.4

Ilya [14]

Answer:

-14.4, -14 1/5, -14.04

Step-by-step explanation:

1/5=0.2

-14..04 is closest to 0 on a number line

the more i think about it the more i doubt myself but i hope its right. pretty sure it is.

3 0

2 years ago

Heeeeeeeeeeelp pleaseeeeeeeeeeee

aleksandrvk [35]

Answer

<2 = <4 = <6 = <8

All of those are 94 degrees

<1 = <3 = <5 + <7

All of those are 86 degrees

Hope this helps :D

7 0

3 years ago

1)a chord of length 18cm midway the radius of a circle. calculate the radius of the circle correct to 1d.p. 2)if two parallel ch

kykrilka [37]

Part 1:

Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.

Thus, half the angle formed by the chord at the centre of the circle is given by:

$\cos\theta=\frac{\left( \frac{1}{2} r\right)}{r}= \frac{1}{2} \\ \\ \Rightarrow\theta=\cos^{-1}\left( \frac{1}{2} \right)=60^o$

Now,

$\sin60^o= \frac{9}{r} \\ \\ \Rightarrow r= \frac{9}{\sin60^o} =10.392$

Therefore, the radius of the circle is 10.4 cm to 1 d.p.

Part 2I:

Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

$\sin\theta= \frac{4}{10} = \frac{2}{5} \\ \\ \theta=\sin^{-1}\left( \frac{2}{5} \right)=23.6^o$

Now,

$\cos23.6^o= \frac{x}{10} \\ \\ \Rightarrow x=10\cos23.6^o=9.165\approx9.2cm$

Part 2II:

Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

$\sin40^o= \frac{y}{10} \\ \\ \\ \Rightarrow y=10\sin40^o=6.428$

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately 12.9 cm.

3 0

3 years ago