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Pavel [41]
2 years ago
13

Help asap for brainiest!

Mathematics
2 answers:
Kryger [21]2 years ago
5 0

Answer:

j is (0,3) k is (-2,3) and l is (-2,0) hope this helps

Fofino [41]2 years ago
3 0

Answer:

j (0,3)

Step-by-step explanation:

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Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20
Naily [24]

Answer:

\displaystyle y = x^{-\frac{2}{3}}

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. \log(pq)=\log p+\log q

2. \displaystyle \log_pq=\frac{1}{\log_qp}

3. \displaystyle \log p^q=q\log p

We are given the equation:

\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }

Applying the second property:

\displaystyle  \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}

Substituting:

\displaystyle \log_{2}(x) = 3\log_{2}(xy)

Applying the first property:

\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))

Operating:

\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)

Rearranging:

\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)

Simplifying:

\displaystyle -2\log_{2}(x) =3\log_{2}(y)

Dividing by 3:

\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}

Applying the third property:

\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)

Applying inverse logs:

\boxed{y = x^{-\frac{2}{3}}}

7 0
3 years ago
What is the surface area and steps to get there
GrogVix [38]
So you want to find the area of each side
8X10=80
8x6=48
8x8=64
10X6=60
80+48+64+60=252
So the surface area is 252 yds
5 0
3 years ago
A rectangle's length is 8 cm longer than
saul85 [17]

Answer:

The Answer is 96 .

Step-by-step explanation:

i hoped it's helpful

thank you ☺️☺️☺️

8 0
3 years ago
What is the equation of the circle whose diameter expands from point A = (-3,-2) to B= (1,4).
blsea [12.9K]
1,4
—— —> 1 divided by -3 or 4 divided by -2
-3,-2
6 0
3 years ago
Explain why 2+x and x+3 are equivalent
wlad13 [49]

Check whether the two expressions 2x+3y2x+3y and 2y+3x2y+3x equivalent.

The first expression is the sum of 2x2x 's and 3y3y 's whereas the second one is the sum of 3x3x 's and 2y2y 's.

Let us evaluate the expressions for some values of xx and yy . Take x=0x=0 and y=1y=1 .

2(0)+3(1)=0+3=32(1)+3(0)=2+0=22(0)+3(1)=0+3=32(1)+3(0)=2+0=2

So, there is at least one pair of values of the variables for which the two expressions are not the same.

5 0
3 years ago
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