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lara31 [8.8K]
3 years ago
11

There are 96 people consisting of 48 married couples in a room. Assuming that no husband or wife shakes thr others hand but ever

yone else shakes hands exactly once, how many handshakes are there?
Mathematics
1 answer:
NikAS [45]3 years ago
6 0

Answer:

4512 handshakes

Step-by-step explanation:

We are told in the question, that there are

96 people in the room = 48 couples

Assuming that no husband or wife shakes each others hand but everyone else shakes hands exactly once

This means

48 couples will shake 94 people because they are excluded

This is calculated as

48 × 94 = 4512 handshakes

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15x - 5 = 180°

15x = 180 + 5

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x = 185/15

x = 12.33

hope this helps you!

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Which equation results from taking the square root of both sides of (x 9)2 = 25? x 3 = ±5 x 3 = ±25 x 9 = ±5 x 9 = ±25.
kow [346]

The equation which is results from taking the square root of both sides of the provided equation is,

(x+9)=\pm5\\

<h3>What is the square root?</h3>

A square root of a number is the value which is when multiplicand by itself gives the same value as the number posses.

Let a number is <em>a. </em>Then this number in the form of square root can be written as,

a=\sqrt{a}\times \sqrt{a}

The given algebraic equation in the problem is,

(x+ 9)^2 = 25

Take the square root, in both sides,

\sqrt{(x+ 9)^2} = \sqrt{25}\\\sqrt{(x+ 9)^2} = \sqrt{5^2}

Cancel out the square root with the square of the number as,

(x+9)=\pm5\\

Hence, the equation which is results from taking the square root of both sides of the provided equation is,

(x+9)=\pm5\\

Learn more about the square root of number here;

brainly.com/question/664132

7 0
2 years ago
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