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marin [14]
3 years ago
8

A 20 ft flag pole casts a shadow 32 ft long. What is the angle of elevation of the sun?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer:

<em>The angle of elevation of the sun is 32°</em>

Step-by-step explanation:

<u>Right Triangles</u>

The flagpole and the ground form a right angle (90°). In triangles with right angles, the trigonometric ratios are satisfied.

Each acute angle has an adjacent leg and an opposite leg. The tangent ratio relates to both legs.

\displaystyle \tan x=\frac{\text{opposite leg}}{\text{adjacent leg}}

The opposite leg to angle x is 20 ft and the adjacent leg is 32 ft, thus:

\displaystyle \tan x=\frac{20}{32}=0.625

Calculate x by using the inverse tangent:

x=\arctan 0.625

x=32^\circ

The angle of elevation of the sun is 32°

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Semenov [28]

Answer:

2kg

Step-by-step explanation:

Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be

H = 2/3 * R

= 2R/3

Given that the 3 bricks weigh 5kg in total then,

2R/3 + R = 5

Multiply through the equation by 3

2R + 3R = 15

5R = 15

Divide both sides by 5

R = 15/5

= 3

The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs

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4 0
3 years ago
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omeli [17]

Answer:

16. y=-5x-20; 17. y=6x+18, or factored y=6(x+3)

Step-by-step explanation:

Your slope is -5

y=-5x+b, solve for b by pluging the point (-3,-5) in for x and y

-5=-5(-3)+b, solve for b

-20=b, now rewrite the equation

y=-5x-20

Your slope is 6

y=-5x+b, solve for b by pluging the point (-3,-0) in for x and y

0=6(-3)+b, solve for b

18=b, now rewrite the equation

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What kind of line is y=3? horizontal, vertical,slanted?
Firdavs [7]

As there is no x axis it will have to be vertical as the y axis is already vertical


7 0
3 years ago
Need help ASAP. i forgot all the steps after the Area is solved with 5. or if 25pi is the right answer.
maxonik [38]

Answer:

42.5\:\mathrm{m^2}

Step-by-step explanation:

The area of a sector with measure \theta in degrees is given by r^2\pi\cdot\frac{\theta}{360}, where r is the radius of the sector.

What we're given:

  • r of 5
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Solving, we get:

A_{sector}=5^2\pi\cdot \frac{195}{360}=13.5416666667\pi=42.5424005174\approx \boxed{42.5\:\mathrm{m^2}}

*Notes:

  • units should be in square meters (area)
  • the problem does not say whether to round or leave answers in term of pi, so you may need to adjust the answer depending on what your teacher specifically wants
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