Can someone help me with this and show their work and how they found the answer?

Mathematics

1 answer:

Semenov [28]3 years ago

4 0

Answer:

2kg

Step-by-step explanation:

Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be

H = 2/3 * R

= 2R/3

Given that the 3 bricks weigh 5kg in total then,

2R/3 + R = 5

Multiply through the equation by 3

2R + 3R = 15

5R = 15

Divide both sides by 5

R = 15/5

= 3

The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs

= 2 * 3/3

= 2kg

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Find the length of a square when the area is 25cm

jeka94

Square's area= length/width^2

so then to find out the length or width (since they are the same in a square) you do the square root of 25 which is 5 since 5 times 5 is 25

so the square's length is 5cm

8 0

3 years ago

Mr. Johnson is working on constructing a square table for his classroom. He positioned his design on a coordinate grid, as shown

sasho [114]

Answer:

This is proved with the help of slope.

Step-by-step explanation:

Given Mr. Johnson is working on constructing a square table for his classroom. He positioned his design on a coordinate grid, as shown. Mr. Johnson will need to put a brace through each diagonal of the table in order to secure the table's stability.

Now, if Johnson use more than one brace then we have to prove that the braces will intersect at a right angle.

From the figure we have to prove the diagonals AC and BD are at right angle. To prove above we have to find the slopes of both diagonals.

$\text{Slope of AC=}\frac{y_2-y_1}{x_2-x_1}=\frac{-5-2}{4-(-3)}=\frac{-7}{7}=-1$