All categories

2 years ago

PLS HELP! it’s question 12

Mathematics

2 answers:

Andrei [34K]2 years ago

7 0

Answer:

yes

Step-by-step explanation:

it is going by 5s.

rusak2 [61]2 years ago

4 0

Answer:

Yes. This is because if you plot the numbers on a ration table or see the graph points, you can see a pattern: you multiply by 5. The equation to solve this would be y=5x. Another reason why this is proportional is that the graph starts from the origin (0,0) This is the opposite for non-proportional relationships. Hope this helps! :)

You might be interested in

Assume that there is a 4% rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive wit

kap26 [50]

Answer:

a) 99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b) 99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

Step-by-step explanation:

For each disk drive, there are only two possible outcomes. Either it works, or it does not. The disks are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

4% rate of disk drive failure in a year.

This means that 96% work correctly, $p = 0.96$

a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 2$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.96)^{0}.(0.04)^{2} = 0.0016$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0016 = 0.9984$

99.84% probability that during a year, you can avoid catastrophe with at least one working drive

b. If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive?

This is $P(X \ geq 1)$ when $n = 4$

We know that either none of the disks work, or at least one does. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.96)^{0}.(0.04)^{4} = 0.00000256$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.00000256 = 0.99999744$

99.999744% probability that during a year, you can avoid catastrophe with at least one working drive

7 0

3 years ago

Can you help me solve this question

IRINA_888 [86]

Answer: Coordinates: (1,3) length RS: 3 length RT: 2 ST: 3.6

Step-by-step explanation:

a^2+b^2=c^2

3^2+2^2=c^2

9+4=c^2

13=c^2

3.6=c

3 0

1 year ago

Graph y−5=−23(x+9) using the point and slope given in the equation.

Mashcka [7]

Answer:

Plot (-9,5) then you do rise over run and go down 2 and to the right 3

Step-by-step explanation:

So your points would be (-9,5) and(-6,3)

6 0

2 years ago

Y is inversely proportional to x. When y=25, x=4 Work out y when x=20

ipn [44]

Answer:

y=5 when x=20

Step-by-step explanation:

Using the format for inverse proportions: y=k/x

To find k, substitute 25 in for y and 4 for x to find:

25=k/4 ⇒ k=100

Using this we can substitute k and x in for 100 and 20 to find:

y=100/20 ⇒ y=5

8 0

2 years ago

Convert 200 centimeters into kilometers

Temka [501]

200 centimetes converted to kilometers = 0.002

5 0

3 years ago