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Lisa [10]
3 years ago
6

PLS HELP! it’s question 12

Mathematics
2 answers:
Andrei [34K]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

it is going by 5s.

rusak2 [61]3 years ago
4 0

Answer:

Yes. This is because if you plot the numbers on a ration table or see the graph points, you can see a pattern: you multiply by 5. The equation to solve this would be y=5x. Another reason why this is proportional is that the graph starts from the origin (0,0) This is the opposite for non-proportional relationships. Hope this helps! :)

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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
HELP ASAPPPP!!! Question in pic. Find the value of x
erik [133]

Answer:

x = 14

Step-by-step explanation:

30 = 3x - 12 (vertically opp)

30 + 12 = 3x

42 = 3x

42÷3 = x

14 = x

5 0
3 years ago
What’s the answer for this question?
loris [4]
Your answer is 16 because you have to multiply b and c but it has to be squared and then you subtract 400 by 144 and get 256 and the square root of that is 16
6 0
3 years ago
1. A store has a rectangular parking lot that is 120 ft by 100 ft. How many square feet of
morpeh [17]

Answer:

Step-by-step explanation:

Parking Standards - Non-Residential Development. 4-12. Annexes. Annex A ... the recommended minimum dimensions for a car space are 4.8 metres by ... to the standing area required for the general type of commercial vehicle ... requirements and detailed layout of parking spaces will be site specific. Car.

4 0
3 years ago
$6,700 is invested in an account earning 8. 3% interest (APR), compounded daily. Write a function showing the value of the accou
aliina [53]

Answer:

  A = $6,700(1 +0.0865^t)

  APY = 8.65%

Step-by-step explanation:

Daily compounding of interest results in an annual growth factor of ...

  gf = (1 +r/365)^365 . . . . for APR = r

Your growth factor is ...

  gf = (1 +0.083/365)^365 ≈ 1.086532

Then the growth rate (APY) is ...

  APY = gf -1 ≈ 8.65%

The account value is multiplied by the growth factor each year, so after t years will be ...

  A = P(1 +APY)^t

  A = $6,700(1 +0.0865)^t . . . . . . . 0.0865 is the annual growth rate

7 0
3 years ago
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