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insens350 [35]
3 years ago
15

Meg conducted a survey of four school cafeterias to find the number of students who like sandwiches for lunch. The results of he

r survey are recorded in the table below:
Which school has the greatest percentage of students who like sandwiches for lunch?

Mathematics
1 answer:
lara31 [8.8K]3 years ago
5 0

Answer:

school A : 12/38 = 0.315 = 31.5%

school B : 9/48 = 0.187 = 18.7%

school C : 10/26 = 0.384 = 38.4%

school D : 8/24 = 0.333 = 33.3%

school C has the greatest percentage

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Which expression is equivalent to (8x^3)^2/3
VARVARA [1.3K]

Answer: 64x^6/3

Step-by-step explanation:

(8x^3)^2/3

8^2(x^3)^3/3

64(x^3)^3/3

64x^6/3

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

4 0
3 years ago
Goods bought for $800 had to be sold off at a loss of 8% the selling price was​
Vikentia [17]

Answer:

8% of 800 is 64

800-64=736

Step-by-step explanation:

4 0
2 years ago
2x + 3 = 4x^2<br> completing the square
ch4aika [34]

Answer:

\frac{1+\sqrt{13} }{4}, \frac{1-\sqrt{13} }{4}

Step-by-step explanation:

First, make them on one side of the formula in the form of ax^2+bx+c=0 which is 4x^{2} -2x-3=0

Next, insert the corresponding number in the quadratic formula, \frac{-b+\sqrt{b^{2}-4ac } }{2a}  ,\frac{-b-\sqrt{b^{2}-4ac } }{2a} , and the answer can be calculated.

6 0
1 year ago
Find the other endpoint when the midpoint is (-2,-4) and one endpoint is (0.4).​ I will give brainly thing
Harlamova29_29 [7]
(-4,-12) I think brainly plzzzzzz
8 0
3 years ago
HELP ASAP Calculate the residuals for your scatterplot in step 2d.
postnew [5]

The residuals of the linear regression equation are -1.36, 0.32, 0.01, 0.62, 0.17, -0.24, 0.89, 0.09, 0.18 and -0.7

<h3>How to determine the residuals?</h3>

The regression equation is given as:

y = 0.141x + 0.842

Next, we calculate the predicted values (y) at the corresponding x values.

So, we have:

y = 0.141 * 13.8 + 0.842 = 2.78

y = 0.141 * 18 + 0.842 = 3.38

y = 0.141 * 16.7 + 0.842 = 3.20

y = 0.141 * 18 + 0.842 = 3.38

y = 0.141 * 0.7 + 0.842 = 0.94

y = 0.141 * 21.9 + 0.842 = 3.93

y = 0.141 * 15.5 + 0.842 = 3.03

y = 0.141 * 9.2 + 0.842 = 2.14

y = 0.141 * 19.5 + 0.842 = 3.59

y = 0.141 * 16.7 + 0.842 = 3.20

The residuals are then calculated using:

Residual = Actual value - Predicted value

So, we have:

Residual = 1.42 - 2.78 = -1.36

Residual = 3.7 - 3.38 = 0.32

Residual = 3.21 - 3.20 = 0.01

Residual = 4 - 3.38 = 0.62

Residual = 1.11 - 0.94 = 0.17

Residual = 3.69 - 3.93 = -0.24

Residual = 3.92 - 3.03 = 0.89

Residual = 2.23 - 2.14 = 0.09

Residual = 3.77 - 3.59 = 0.18

Residual = 2.5 - 3.20 = -0.7

Hence, the residuals of the linear regression equation are -1.36, 0.32, 0.01, 0.62, 0.17, -0.24, 0.89, 0.09, 0.18 and -0.7

Read more about residuals at:

brainly.com/question/16180255

#SPJ1

6 0
1 year ago
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