Can you simply these fractions?

Mathematics

1 answer:

andrew11 [14]3 years ago

8 0

1/4, 3/5, 1/9, 1/10, 3/7, 3/4, 5/6, 1/6, 1/5, 2/3 :))

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Write (5,0) with a slope of 2 in point-slope form.

neonofarm [45]

Y = mx + c
m = 2
y = 2x + c

At (5, 0)
0 = 2(5) + c
c = -10

y = 2x - 10

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4 years ago

Use the distributive property’s remove the parentheses in the following expression. 8(m+5)=

Nookie1986 [14]

Answer:

8m + 40 = ???

Step-by-step explanation:

8m = -40

m = -5

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3 years ago

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At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2.

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4 years ago

An obtuse angle in the figure is

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Obtuse angles are more than 90° and less than 180°

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Can someone help me please

Tomtit [17]

It would affect the mean the most

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3 years ago