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2 years ago

12

There are 45 students who play a woodwind instrument in the school band. Of these, 18 play the saxophone. What percent of the wo

odwind musicians play the saxophone?

1 answer:

Drupady [299]2 years ago

6 0

40% of students who play the saxophone
18/45= .4 = 4/10*10/10= 40/100= 40%

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At the beginning of the season, MacDonald had to remove

icang [17]

Answer:

heehfbhjbC EAEJ

Step-by-step explanation:

JKNKAJAR

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3 years ago

Thanks for the help!

valentinak56 [21]

<h3>Answer: 103</h3>

Explanation:

The term "bisect" means "divide in half", or "divide in two equal pieces".

Angles A = 58 and B = 96 divide in half to get 29 and 48 respectively

Find their sum and subtract it from 180 to get angle AMB

29+48 = 77

180-77 = 103

A diagram is shown below.

4 0

1 year ago

Solve the system using elimination: -3x - 3y = 12 -9x + 3y = -24<br><br>The answer is not (-1,-3)

FinnZ [79.3K]

Answer:

{x = 1, y = -5

Step-by-step explanation:

Solve the following system:

{-3 x - 3 y = 12 | (equation 1)

{3 y - 9 x = -24 | (equation 2)

Swap equation 1 with equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

{-(3 x) - 3 y = 12 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:

{-(9 x) + 3 y = -24 | (equation 1)

0 x - 4 y = 20 | (equation 2)

Divide equation 1 by 3:

{-(3 x) + y = -8 | (equation 1)

{0 x - 4 y = 20 | (equation 2)

Divide equation 2 by 4:

{-(3 x) + y = -8 | (equation 1)

{0 x - y = 5 | (equation 2)

Multiply equation 2 by -1:

{-(3 x) + y = -8 | (equation 1)

{0 x+y = -5 | (equation 2)

Subtract equation 2 from equation 1:

{-(3 x)+0 y = -3 | (equation 1)

{0 x+y = -5 | (equation 2)

Divide equation 1 by -3:

{x+0 y = 1 | (equation 1)

{0 x+y = -5 | (equation 2)

Collect results:

Answer: {x = 1 , y = -5

5 0

3 years ago

Dan has a board that is 8 3/4 feet long. He cuts off 4 5/6 feet and says he has 4 1/12

Ilia_Sergeevich [38]

Answer:

C

Step-by-step explanation:

The answer to this problem is 3 11/12.

1.8 3/4= 8 9/12

2.4 5/6 = 4 10/12

if you minus the two numbers, you get 3 11/12.

3 0

3 years ago

Read 2 more answers

Ryan flew from Wiley Post to Ponca City and back. Ryan maintained an average rate of 450 mph going to Ponca City and an average

Reil [10]

The answer is B, and here's why. Set up a table for "there" and "back" and use the distance = rate * time formula, like this:
               d             r            t
there       d           450         t
back        d           400        1-t

Let me explain this table to you. The distance is d, we don't know what it is, that's what we are actually looking for. We only know that if we go somewhere from point A to point B, then back again to point A, the distance there is the same as the distance back. Hence, the d in both spaces. There he flew 450 mph, back he flew 400 mph. If the total distance was 1 hour, he flew an unknown time there and one hour minus that unknown time back. For example, if he flew for 20 minutes there, one hour minus 20 minutes means that he flew 60 minutes - 20 minutes = 40 minutes back. See? Now, because the distance there = the distance back, we can set the rt in both equal to each other. If d = rt there and d = rt back and the d's are the same, then we can set the rt's equal to each other. 450t = 400(1-t) and
450t = 400 - 400t and 850t = 400. Solve for t to get t = .47058. Now, t is time, not the distance and we are looking for distance. So multiply that t value by the rate (cuz d = r*t) to get that the distance one way is
d = 450(.470580 and d = 211. 76 or, rounded like you need, 212.

4 0

3 years ago