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Maurinko [17]
3 years ago
13

Two objects, X and Y, move toward one another and eventually collide. Object X has a mass of 2M and is moving at a speed of 2vo

to the right before the collision. Object Y has a mass of M and is moving at a speed of vo to the left before the collision. Which of the following describes the magnitude of the forces F the objects exert on each other when they collide?
a. The force exerted by X on Y is 4F to the right, and the force exerted by Y on X is F to the left.
b. The force exerted by X on Y is 2F to the right, and the force exerted by Y on X is F to the left.
c. The force exerted by X on Y is F to the right, and the force exerted by Yon X is F to the left.
d. The force exerted by X on Y is F to the left, and the force exerted by Y on X is F to the right.
Physics
1 answer:
Nady [450]3 years ago
3 0

Answer:

The force exerted by X on Y is F to the right, and the force exerted by Yon X is F to the left.

Explanation:

There are two objects X and Y. Mass of object X is 2M, that is moving with a speed of 2v_o and that of object Y is M that is moving with a speed of v_o.

When both of the objects collide, the magnitude of the forces F the objects exert on each other is equal to :

The force exerted by X on Y is F to the right, and the force exerted by Yon X is F to the left using Newton's third law of motion. Hence, the correct option is (c).

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     sin θ₂ = n₁ / n₂ sin θ₁

The index of air refraction is n₁ = 1

The angle is this equation is measured between the vertical line called normal, if the angles are measured with respect to the surface

     θ_s = 90 - θ

     θ_s = 90- 43.5

     θ_s = 46.5º

     sin θ₂ = 1 / 1.68  sin 46.5

     sin θ₂ = 0.4318

     θ₂ = 25.6º

The angle with respect to the surface is

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     θ₂_s = 64.4º

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This question involves the concepts of the equations of motion, kinetic energy, and potential energy.

a. The kinetic energy of the rocket at launch is "3.6 J".

b. maximum gravitational potential energy of the rocket is "3.6 J".

<h3>a. KINETIC ENERGY AT LAUNCH</h3>

The kinetic energy of the rocket at launch is given by the following formula:

K.E=\frac{1}{2} m v_i^2

where,

  • K.E = initial kinetic energy = ?
  • m = mass of rocket = 0.05 kg
  • v_i = initial speed = 12 m/s

Therefore,

K.E=\frac{1}{2}(0.05\ kg)(12\ m/s)^2

K.E = 3.6 J

<h3>b. MAXIMUM GRAVITATIONAL POTENTIAL ENERGY</h3>

First, we will use the third equation of motion to find the maximum height reached by rocket:

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Therefore,

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Hence, the maximum gravitational potential energy will be:

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P.E = 3.6 J

Learn more about the equations of motion here:

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