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sergeinik [125]
3 years ago
9

Choose a substance you're familiar with. what are its physical and chemical properties? How would you measure its density? What

are some physical and chemical changes it can undergo?
Physics
1 answer:
Gekata [30.6K]3 years ago
6 0
<span>you can look at magnesium, it can react with oxygen to form oxides. (chemical) it is malleable and a solid at room temperature. (physical)

</span><span>to measure its density, the mass and volume can be worked out and from this density too. look up the equation, it is quite easy :) 
</span><span>physical changes -- it can be melted, and oxidized 

</span><span>the chemical changes of oxidation magnesium looses electrons to form oxides, this is a chemical reaction- chemical change..--- use to get the density use (rho) or density D = M/V</span>
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If a rigid body rotates about a fixed axis passing through its center of mass, the body's linear momentum is
dexar [7]

Answer:

The linear momentum is zero

Explanation:

Because

When a rigid body is rotating about a fixed axis passing through point O, the body’s linear momentum given as L = mvG

But VG= 0 so

Linear momentum is zero

6 0
3 years ago
How does a mathematical model help you understand the science concepts
Dmitrij [34]
It can help with measurements and when you want to add measurements to a cylinder or a beaker so ya
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kykrilka [37]

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Clouds form when below the dew point

4 0
3 years ago
How do you work out how many atoms there are in a isotope?
GalinKa [24]
206Pb = 1.342 x10^22 atoms 

<span>To find the number of atoms, you must first find the number of moles. If 238U is 238.029g/mol, and we have 1.75 grams, how many moles is that? 1.75 divided by 238.029 = 0.007352045 moles. To find the number of atoms in 0.007352045 moles, you multiply by a mole: </span>
<span>0.007352045 x 6.02 x 10^23 = 4.426 x10^21 atoms. </span>

<span>Same procedure for 206Pb: </span>
<span>4.59 divided by 205.97446 = 0.022284316 moles </span>
<span>0.022284316 x 6.02 x 10^23 = 1.342 x10^22 atoms. </span>

<span>Hope that helps you!
https://answers.yahoo.com/question/index?qid=20100331153014AAoMXcu
</span>
4 0
4 years ago
Calculate the standard electrode potential difference (e°) of the daniell cell (at 1 bar) if temperature is 473.15 k.
anzhelika [568]
Missing data in the text of the exercise: The molar concentration of Zinc is 10 times the molar concentration of copper.

Solution:

1) First of all, let's calculate the standard electrode potential difference at standard temperature. This is given by:
E^0=E_{cat}^0-E_{an}^0
where E_{cat}^0 is the standard potential at the cathode, while E_{an}^0 is the standard potential at the anode. For a Daniel Cell, at the cathode we have copper: E_{Cu}^0=+0.34 V, while at the anode we have zinc: E_{Zn}^0=-0.76 V. Therefore, at standard temperature the electrode potential difference of the Daniel Cell is
E^0=+0.34 V-(-0.76 V)=+1.1 V

2) To calculate E^0 at any temperature T, we should use Nerst equation:
E^0(T)=E^0- \frac{R T}{z F} \ln  \frac{[Zn]}{[Cu]}
where 
R=8.31 J/(K mol)
T=473.15 K is the temperature in our problem
z=2 is the number of electrons transferred in the cell's reaction
F=9.65\cdot 10^4 C/mol is the Faraday's constant
[Zn] and [Cu] are the molar concentrations of zinc and in copper, and in our problem we have [Zn]=10[Cu].
Using all these data inside the equation, and using E^0=+1.1 V, in the end we find:
E^0(T)=E^0- \frac{R T}{z F} \ln \frac{[Zn]}{[Cu]}=+1.053 V
8 0
3 years ago
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