#include
#include
using namespace std;
int main(){
int input[] = {-19, 34, -54, 65, -1};
std::vector voutput:
std::vector vinput (input, input + sizeof(input) / sizeof(int) );
for (std::vector::iterator it = vinput.begin(); it != vinput.end(); ++it)
if(*it > 0) voutput.insert(voutput.begin(), *it);
for(std::vector::iterator it = voutput.begin(); it < voutput.end(); ++it)
std::cout << *it << ‘\n’ ;
return 0;
}
Answer:
#include <stdio.h>
int fib(int n) {
if (n <= 0) {
return 0;
}
if (n <= 2) {
return 1;
}
return fib(n-1) + fib(n-2);
}
int main(void) {
for(int nr=0; nr<=20; nr++)
printf("Fibonacci %d is %d\n", nr, fib(nr) );
return 0;
}
Explanation:
The code is a literal translation of the definition using a recursive function.
The recursive function is not per se a very efficient one.
Answer:
Solution part of the question:
if(userTickets>5) //compare the value of userTickets with 5.
awardPoints = 10; // assign the 10 value to the award point
else
awardPoints=userTickets;// assign the userticket value to the awardpoint.
Output:
For the input 4 the output is 4.
For the input 5 the output is 5.
For the input 6 the output is 10.
For the input 7 the output is 10.
Explanation:
All the other part of the program is given on the question so here only if-else statement is given on the answer part. Which is pasted at the place of "/* Your solution goes here */" and the user can get the right answer.
- In the "if" statement the value of "userTickets" variable is get compared by 5 and if it is greater than 5 than variable "awardpoint" assigns the '10' value.
- Otherwise, with the help of "else" statement "userticket" variables value (which is the input value for the program) assign to the "awardpoint" variable.
Cleaning up a system helps clear up the space on the drives. It may also clear up processor usage, ram usage if you uninstall programs that automatically started when the system booted. You may also delete some unwanted programs in the process.
D: fit to size because it has to fit whatever your putting it on
