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Maslowich
3 years ago
8

Three friends arrive at a party their arrival increases the number of people at the party by 20% in total how many people are no

w at the party
Mathematics
1 answer:
rodikova [14]3 years ago
5 0

Answer:

18 people

Step-by-step explanation:

Let the number of people at the party before the arrival be x

20% of x = 3

20/100 * x = 3

20x = 300

x = 300/20

x = 15

Adding the friends , we have 15 + 3 = 18

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Reflection acrossed the y axis 
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3 years ago
Veterinarian jasmin cato has 5/9 of a quart of medication, she wishes to prescribe this medication for 6 cats in her pet hospita
Diano4ka-milaya [45]
\frac{5}{9} \div 6 = \frac{5}{9} \div \frac{6}{1} = \frac{5}{9} \times \frac{1}{6} = \frac{5}{54}
Each cat will get 5/54th of a quart or .093 quarts.
5 0
4 years ago
Find the volume of a cube that measures 3 ft high
ValentinkaMS [17]

Answer:

27ft^3

Step-by-step explanation:

3^3 is 27

5 0
3 years ago
How do you do this question?
vaieri [72.5K]

Answer:

(-∞, -2), (-2, -0.618), and (1.618, 3)

Step-by-step explanation:

The red plus (+) signs indicate the regions in which the function is concave up, and the red negative (-) signs indicate the regions in which the function is concave down.

Note that the sign of the concavity changes at an inflection point.

Let's examine the intervals given.

(-∞, -2): Yes, concave up.

(-∞, -1.17): No. Concave up in (-∞, -2) but concave down in (-2, -1.17).

(-2, 0): No. Concave down in (-2, -1.17) but increasing in (-1.17, 0.0).

(-1.17, 0.689): Yes. Concave up.

(-0.618, 1.618): No. Concave up in (-0.618, 0.689) but concave down in (0.689, 1.618).

(0, 3): No. Concave up in (0, 0.689), concave down in (0.689, 2.481), and concave up in (2.481, 3).

(2.481, ∞): Yes. Concave up.

The three intervals that are concave up are (-∞, -2), (-1.17, -0.689), and (2.481, ∞).

4 0
3 years ago
Find the midpoint P(16,7) and Q(12, -3) With work.
hichkok12 [17]

Answer:

(14, 2 )

Step-by-step explanation:

Use the midpoint formula

[0.5(x₁ + x₂), 0.5(y₁ + y₂) ]

with (x₁, y₁ ) = (16, 7) and (x₂, y₂ ) = (12, - 3)

midpoint = [0.5(16 + 12), 0.5(7 - 3) ] = [0.5(28), 0.5(4) ] = (14, 2 )

8 0
3 years ago
Read 2 more answers
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