Question

❤️ i need this last question

Answer 1

Answer: $10\left(\cos90^{\circ}+i\sin90^{\circ}\right)$

Step-by-step explanation:

Given

The complex number is $z_1=0+10i$

Complex number in polar form is given by

$z=r\left(\cos \theta +i\sin \theta\right)$

Compare it with the given complex number

$r=10$ and $\sin \theta=1$ which implies $\theta$ must be $90^{\circ}$

So, in the polar form, it is

$z_1=10\left(\cos90^{\circ}+i\sin90^{\circ}\right)\\z_1=10e^{i\frac{\pi}{2}}$