Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z= where
- p1 is the sample proportion of public university students who attended at least one class reunion ()
- p2 is the sample proportion of private university students who attended at least one class reunion ()
- p is the pool proportion of p1 and p2 ()
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z= =-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.
Answer:
B. 93%
Step-by-step explanation:
Find the z-score:
z = (x − μ) / σ
z = (122 − 100) / 15
z = 1.47
Find the probability using a calculator or z-score table.
P(Z < 1.47) = 0.93
The answer i pretty sure would be 3x
If I am not mistaken, you cross multiply then divide.
Answer:
Step-by-step explanation:
is the proportionality constant.
The is the independent variable and is the dependent variable.
The proportionality constant is .