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Luden [163]
3 years ago
11

Write the equation of the circle in general form. Show all of your work

Mathematics
2 answers:
finlep [7]3 years ago
8 0
<h2>1. What are the center and equation of the circle?</h2>

In this exercise we have the general form of the equation of a circle, which is given by:

x^2+y^2+18x+4y+49=0

The ordinary equation of a circle is:

(x-h)^2+(y-k)^2=r^2 \\ \\ Developing \ this \ equation: \\ \\ x^2+y^2-2hk-2ky+h^2+k^2-r^2=0

But this can be written as:

x^2+y^2+Dx+Ey+F=0 \\ \\ D=-2h, \ E=-2k, \ and \ F=h^2+k^2-r^2

From the original equation we know that:

D=18, \ E=4, \ and \ F=49 \\ \\ So: \\ \\ h=-\frac{18}{2}=9, \ k=-\frac{4}{2}=2, \ and \ r=\sqrt{9^2+2^2-49}=6

Finally:

\boxed{CENTER: \ (h,k)=(9,2)} \\ \\ \boxed{RADIUS: \ 6}

<h2>2. Write the equation of the circle in general form.</h2>

We need to write this equation in the form:

x^2+y^2+Dx+Ey+F=0

Since:

D=-2h, \ E=-2k, \ and \ F=h^2+k^2-r^2

Then we need to find the center and radius in order to get D, E and F then. From the graph, it is easy to know that the center is (h,k)=(-3,4) and the radius is 2. Therefore:

D=-2(-3)=6, \ E=-2(4)=-8, \ and \ F=(-3)^2+(4)^2-(2)^2=21

Finally, the general form of the equation is:

\boxed{x^2+y^2+6x-8y+21=0}

<h2>3. Write the equation of the parabola</h2>

A parabola is the set of all points in a plane that are equidistant from  a fixed line called the directrix and a fixed point called the focus that does not lie on the line. Since the directrix is x=2 then this is a horizontal axis. So the standard for of the equation of a parabola that matches this form is:

(y-k)^2=4p(x-h) \ \ p \neq 0

The vertex is (h,k)=(-5,8) so our goal is to find p:

(y-8)^2=4p(x+5)

We can find the absolute value of p as follows:

\left|p\right|=2-(-5)=7

Since the directrix is to the left of the vertex, the parabola opens to the left and hence:

p.

Finally, the equation is:

(y-8)^2=4(-7)(x+5) \\ \\ \boxed{(y-8)^2=-28(x+5)}

Assoli18 [71]3 years ago
4 0

Answer: The answer is x^2 + y^2 + 6x - 8y + 21 = 0.

Step-by-step explanation:

First find the original standard form equation of the circle.

So the circle has a center of (-3, 4) and a radius of 2. Write this in standard form:

(x + 3)^2 + (y - 4)^2 = 2^2

Simplify:

(x + 3)^2 + (y - 4)^2 = 4

(x^2 + 6x + 9) + (y^2 - 8y + 16) = 4

Gather like terms:

x^2 + y^2 + 6x - 8y + 9 + 16 - 4 = 0

x^2 + y^2 + 6x - 8y + 21 = 0

There you go!

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