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SpyIntel [72]
3 years ago
11

Simplify csc θ(1−cos^2 θ)/sinθ cos θ to a single trigonometric function

Mathematics
1 answer:
topjm [15]3 years ago
6 0

Answer:

<u><em></em></u>\frac{cosec\alpha(1-cosx^{2} \alpha ) }{sin\alpha cos\alpha  } = sec\alpha<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the trigonometric function

            \frac{cosec\alpha(1-cosx^{2} \alpha ) }{sin\alpha cos\alpha  }

  we know that    sin²∝ + cos²∝ = 1

                      ⇒    sin²∝ = 1- cos²∝

Now we have to simplify the given trigonometric function

                =       \frac{cosec\alpha(sin^{2} \alpha  ) }{sin\alpha cos\alpha  }

               =       \frac{cosec\alpha(sin \alpha  ) }{ cos\alpha  }

<u><em>Step(ii)</em></u>

         we know that  cosec∝ = 1/ sin∝

              = \frac{\frac{1}{sin\alpha } (sin \alpha  ) }{ cos\alpha  }

    After cancellation sine function, we get

          =  \frac{1 }{ cos\alpha  } = sec\alpha

<u><em>Final answer:-</em></u>

<u><em></em></u>\frac{cosec\alpha(1-cosx^{2} \alpha ) }{sin\alpha cos\alpha  } = sec\alpha<u><em></em></u>

           

     

 

               

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