Answer:
true
Step-by-step explanation: true
Let the four consecutive integers be
x , x+1, x+2, x+3
ATQ, Their sum is 18
<h3>Now,</h3>
- 1st number = x = 3
- 2nd number = x+1 = 3+1 = 4
- 3rd number = x+2 = 3+2 = 5
- 4th number = x+3 = 3+3 = 6
<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>
Responder:
<em>a) 1
</em>
<em>b) 12
</em>
<em>c) 3
</em>
<em>d) -1 y 3
</em>
Explicación paso a paso:
Dadas las siguientes ecuaciones;
a) x²-x =0
x² = 0+x
x² = x
x = 1
b) -x²+12x = 0
-x² = -12x
x² = 12x
x = 12
c) 3x² - 9x = 0
Suma 9x a ambos lados
3x²-9x+9x = 0+9x
3x² = 9x
3x = 9
x = 9/3
x = 3
d) x²-2x-3 = 0
x²-3x+x-3 = 0
x(x-3)+1(x-3) = 0
(x+1)(x-3) = 0
x+1 = 0 y x-3 = 0
x = -1 y 3
Answer:
I cannot answer this. There are no letters. I am sorry that I couldn't help you.
Step-by-step explanation:
Answer:
The third one is
but I am unsure of the other two I will try to figure it out right now
Step-by-step explanation:
