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3 years ago

What is the height, x, of the equilateral triangle shown?

Mathematics

1 answer:

Alex_Xolod [135]3 years ago

3 0

Answer:

Step-by-step explanation:

- Divide the base by 2

10 / 2 = 5 in

- multiply by √3

5√3 in

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What is the answer for -5x^2=-500 by factoring the quadratic equation?

evablogger [386]

Answer:

x=10

Step-by-step explanation:

I think..i tired

Divide both sides by 55.

{x}^{2}=-\frac{500}{5}x2=−5500

Simplify \frac{500}{5}5500 to 100100.

{x}^{2}=-100x2=−100

Take the square root of both sides.

x=\pm \sqrt{-100}x=±√−100

Simplify \sqrt{-100}√−100 to \sqrt{100}\imath√100ı.

x=\pm \sqrt{100}\imathx=±√100ı

Since 10\times 10=10010×10=100, the square root of 100100 is 1010.

5 0

3 years ago

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FinnZ [79.3K]

Answer:

-8a^12b^6

Step-by-step explanation:

multiply each term with the power

4 0

3 years ago

Troy and Lazetta are solving the following word problem:

laila [671]

Answer:

1). 35.5

2).commutitive property of addition

3).Both

Step-by-step explanation:

1). 35.5

2).commutitive property of addition

3).Both

6 0

3 years ago

Brooke found the equation of the line passing through the points (–7, 25) and (–4, 13) in slope-intercept form as follows.

Arturiano [62]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

$m = \frac {y2-y1} {x2-x1}$

We have the following points:

$(x1, y1): (- 7,25)\\(x2, y2): (- 4,13)$

Substituting the values: $m = \frac {13-25} {- 4 - (- 7)} = \frac {-12} {- 4 + 7} = \frac {-12} {3} = - 4$

Thus, the line is of the form:

$y = -4x + b$

We substitute one of the points and find "b":

$13 = -4 (-4) + b\\13 = 16 + b\\b = 13-16 = -3$

Finally we have to:

$y = -4x-3$

Answer:

The equation es $y = -4x-3$

6 0

3 years ago

Read 2 more answers

I have to solve the system of linear equations by elimination. i also have to check my solution.

Travka [436]

Answer:

$x=1$ , $y=6$

Step-by-step explanation:

Give.

$x+2y=13$ ----------(1)

$-x+y=5$ ------------(2)

Solve this linear equation by elimination method.

Add equation 1 and 2

$x+2y=13$

$-x+y=5$

-----------------------------

$0+3y=18$

$3y=18$

$y=\frac{18}{3} \\y=6$

Put y value in equation 2

$-x+6=5$

$-x=5-6$

$-x=-1$

$x=1$

$x=1$ , $y=6$

6 0

3 years ago