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Ugo [173]
3 years ago
11

How do I factorise 6-42x

Mathematics
2 answers:
Nataly_w [17]3 years ago
6 0

Answer:

6(-7x+1)

Step-by-step explanation:

Given: The equation 6-42x.

To find: Factorize the given equation.

Solution:

The given expression is:

6-42x

which can be rewritten as:

-42x+6

Upon solving the above expression and Taking 6 common from both the terms of the expression ,we get

6(-7x+1)

which is the required factorized form of the given expression.

Zepler [3.9K]3 years ago
4 0

FACTORING: 6 - 42x

STEPS:
 
6 - 42x

-42x + 6

= -6(7x - 1)

FINAL ANSWER: -6(7x - 1)

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Use the distributive property for this expression: 6(2x+5y)
posledela
(6 times 2x) + (6 times 5y)

5 0
3 years ago
Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a
Anit [1.1K]

Answer:

Analyzed and Sketched.

Step-by-step explanation:

We are given y=\frac{\ln\left(5x)}{x^2}

To sketch the graph we need to find 2 components.

1) First derivative of y with respect to x to determine the interval where function increases and decreases.

2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

y'=\frac{1-2\ln\left(5x)}{x^3}=0

x = \sqrt e/5 is absolute maximum

y''=\frac{6\ln\left(5x)-5}{x^4}=0

x=e^{5/6}/5 is the point concavity changes from down to up.

Here, x = 0 is vertical asymptote and y = 0 is horizontal asymptote.

The graph is given in the attachment.

4 0
3 years ago
A seamstress has 1/4 of a foot of thread.Then she uses 1/5 of a foot of thread to sew a hole How much of the thread is left?
Whitepunk [10]
1/10 of the thread is left because a connected to b is the thread and minus the 1/5 is 1/10 since 1/3 +total thread to begin wit.
3 0
3 years ago
Read 2 more answers
Plzz help i dont understand
tangare [24]
There's no picture up
7 0
3 years ago
What is the term of a 7-term geometric series if the first term is -11 the last term is -45,056 and the common ratio is -4
shutvik [7]
I assume you mean to ask how to find the sum of the seven terms?

You have

a_2=ra_1
a_3=ra_2=r^2a_1
a_4=ra_3=r^3a_1
...
a_7=ra_6=r^6a_1

So the sum is

a_1+ra_1+r^2a_1+\cdots+r^6a_1=a_1(1+r+r^2+\cdots+r^6)=a_1\times\dfrac{1-r^7}{1-r}

You know that a_1=-11 and r=-4, so the sum is equal to

-4\times\dfrac{1-(-4)^7}{1-(-4)}=-13108
8 0
3 years ago
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