The correct answer for the question that is being presented above is this one: "b)70 ml." the patient's end-systolic volume (ESV in ml) is <span>b)70 ml.
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The correct answer for the question that is being presented above is this one: "a) passive stretch, contracted, relaxed." The sequence of manipulations will lead to increasing A-band width is that <span>passive stretch, contracted, relaxed.</span>
Answer: 4282.928 = 4283 years
Explanation:
Data given;
Carbon 14 half life = 5740
No (initial radiation) = 0.230 Bq/g
Nf (final radiation) = 0.137 Bq/g
First we find the decimal fraction of the remaining half life of the carbon 14
k = No / Nf
k = (0.137 / 0.230) = 0.595652
So to find how many half-life has elapsed, we say
(1/2)^n = k
(1/2) ^n = 0.595652
Therefore
n log 0.5 = log 0.595652
n = ( log 0.595652) / ( log 0.5)
n = 0.747457
To get the elapsed time or how old the sample is;
We say
Carbon 14 half-life × n
5730 yrs × 0.747457
= 4282.928
= 4283 years.
So the sample of the wood is 4283 years old.
Whether the effect of a neurotransmitter is excitatory or inhibitory depends on the receptor it binds to.
<h3>What is Neurotransmitter?</h3>
A neurotransmitter may be defined as the chemical substances present within the synaptic vesicles and transmitting the impulse through synapses.
Examples of excitatory neurotransmitters are glutamate, norepinephrine, epinephrine, etc. Such neurotransmitters promote the electrical impulse and allow the passage of messages.
Examples of inhibitory neurotransmitters are serotonin, glycine, GABA, etc. Such neurotransmitters inhibit the passage of electrical impulses and block information.
Therefore, it is well described above.
To learn more about Neurotransmitters, refer to the link:
brainly.com/question/26387085
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The Kerbs Cycle occurs in the, D.mitochondria
Answer:
Tertiary.
Explanation:
Primary structure of proteins refers to the order of amino acids that make up the protein. The heme is an nonprotein non-amino acid, so it is not involved at this stage.
Tertiary structure of proteins is the overall 3-D folding of the protein (it comes after secondary, which involves folding into a repeated pattern). The heme bonds to its correct position on the hemoglobin during this stage and helps in correct folding.
