Answer
Answer
The speedometer is likely to show the speed is either 36.0 mph or 44.0 mph.
To prove
Formula

Where error = |Approx value - Exact value |
First case
As given
A speedometer has a percent error of 10%. The actual speed of the car is 40 mph.
Here
Percentage error = 10%
Exact value = 40 mph
error = - (Approx value - Exact value )
= - (Approx value - 40 )
= - Approx value + 40
Put in the formula


Thus
Approx value = 40 - 4
Approx value = 36 mph
Therefore Option (b) is correct .
Second Case
error = (Approx value - Exact value )
= (Approx value - 40 )
= Approx value - 40
Put in the formula


Thus
Approx value = 40 + 4
Approx value = 44 mph
Therefore Option (c) is correct .
Answer: 64
There is 1 favorable outcome out of 36 possible but more likely 64 is the answer
Step-by-step explanation:
Answer:
P = 25.71 cm
Step-by-step explanation:
Perimeter of semicircle = πD/2
Where D=10 cm
P = (3.142)(10)/2
P = (3.142)(5)
P = 15.71 cm
Complete Perimeter of Semicircle = P + Diameter
= 15.71 + 10
= 25.71 cm
Answer:
x = 8, y = 6
Step-by-step explanation:
2x + 5y = 46______(1)
3x - 2y = 12_______(2)
(1) x 3 --> 6x + 15y = 138
(2) x 2 --> 6x -4y = 24
(1) - (2) --> 19y = 114
y = 6 sub into (2)
3x - (2 x 6) = 12
3x = 24
x = 8
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