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dybincka [34]
3 years ago
9

Bruce Wayne trabaja en un proyecto inmobiliario, éste consiste en un edificio con forma de prisma de base triangular, cuya plant

a baja se caracteriza por tener una piscina, un gimnasio y una cancha deportiva. Batman tiene este bosquejo de dicho proyecto: Los terrenos destinados para la piscina, el gimnasio y la cancha deportiva son cuadrados, de modo que la superficie de la cancha es de 2.500 m2 y la de la piscina es de 1.600 m2 . ¿Cuál es la superficie destinada al gimnasio?
Mathematics
1 answer:
Greeley [361]3 years ago
7 0

Answer:

El área del gimnasio sería 2000 metros cuadrados

Step-by-step explanation:

Un lado del gimnasio será igual al lado de la cancha y el otro lado será igual al lado de la piscina.

Dado que tanto la cancha como la piscina tienen forma cuadrada. El lado de la cancha será raíz cuadrada de 2.500 m2 y el de la piscina será raíz cuadrada de 1.600 m2

Por lo tanto, el lado del gimnasio sería 50 y 40.

El área del gimnasio sería 50 * 40 = 2000 metros cuadrados

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1/3

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3 years ago
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There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val
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Answer:

There are 38 premium tickets and 82 regular tickets in a pile.

Step-by-step explanation:

Given,

Total number of tickets = 120

Total amount = $5812

Solution,

Let the number of premium tickets be x.

And the number of regular tickets be y.

Total number of tickets is the sum of total number of premium tickets and  total number of regular tickets.

So the equation can be written as;

x+y=120\ \ \ \ \ equation\ 1

Again,total amount  is the sum of total number of premium tickets multiplied by cost of each premium ticket and  total number of regular tickets multiplied by cost of each regular ticket.

So the equation can be written as;

99x+25y=5812\ \ \ \ equation\ 2

Now We will multiply equation 1 by 25 we get;

x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3

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(99x+25y)-(25x+25y)=5812-3000\\\\99x+25y-25x-25y=2812\\\\74x=2812\\\\x=\frac{2812}{74}=38

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x+y=120\\38+y=120\\y=120-38\\y=82

Hence There are 38 premium tickets and 82 regular tickets in a pile.

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