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katrin2010 [14]
3 years ago
8

On the number line below, P represents a number. What is the value of the opposite of that number? A number line from negative 4

to positive 4 in increments of 1 over 4, with all whole numbers alone labeled is shown. Put point P at the third tick mark to the right of 0. (1 point) a negative 3 over 4 b negative 1 over 4 c 3 over 4 d 1 and 2 over 4
Mathematics
2 answers:
Arada [10]3 years ago
5 0

Answer:

-1 and 2/4

Step-by-step explanation:

Mama L [17]3 years ago
5 0

Answer:

-1 and 2/4

Step-by-step explanation:

i took the pre test and got everything right

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NEED HELP ASAP! 15 points!
sertanlavr [38]

Step-by-step help:

399 - 75 = 324.

Now that we have the bonus out of the equation, the fraction is approximately

324/12.

Divide by 2,

162/6

Divide by 2 again,

81/3.

81 divided by 3 is 27.

So,

The answer is exactly 27.

Hope that helped!

I think maybe the first or second number line.

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3 years ago
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Hunter-Best [27]
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Eddie O'Neil found a sports car advertised at a local used-car dealership for
ludmilkaskok [199]

Answer:

Eddie O'Neil found a car advertised at a local used-car dealership for $34,000. The car is clean and in good condition. Its average retail value is $33,400.

Step-by-step explanation:

4 0
3 years ago
Somebody please help with the ones I got wrong
iren2701 [21]

Answer:

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Step-by-step explanation:

5 0
3 years ago
If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?
lbvjy [14]

Answer:

The domain is \{x ∈ R|x\neq 2\}

Step-by-step explanation:

Given the fucntion c(x):

c(x)=\frac{5}{x-2}

And the function d(x):

d(x) = x + 3

You must multiply them in order to get (cd)(x). Then, this is:

(cd)(x)=(\frac{5}{x-2})(x + 3)\\\\(cd)(x)=\frac{(5)(x+3)}{x-2}\\\\(cd)(x)=\frac{5x+15}{x-2}

You can notice that it is a Rational function.

Since the denominator cannot be zero, the domain of this function will be all the real numbers except those that makes the denominator zero.

Then, you must equate the denominator to zero and solve for "x":

x-2=0\\x=2

Therefore, the domain is \{x ∈ R|x\neq 2\}

5 0
3 years ago
Read 2 more answers
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