Her average in first three test = 89
This means, her total scores in first three test were = 3 x 89 = 267
Her average in four tests = 91
This means, her total scores in four tests are = 364
267 give the sum of first three test scores. and 364 give the sum of scores with fourth test adding in three tests.
So, subtracting 267 from 364 will give us the scores of Fourth test.
Scores of Fourth test = 364 - 267 = 97
Thus, Samantha's Claim is correct
Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
V=763.02
If rounded to the nearest tenth V=763
Answer:
c. 24 is a solution
Step-by-step explanation:
Given equation:
To test the numbers 22, 23, 24, 25 for the solution.
Solution:
In order to test the given number for the solution, we will plugin each number in the unknown variable 
and see if it satisfies the equation.
1) 
Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.
The above statement can never be true and hence 22 is not a solution.
2) 
The fractions can no further be reduced.
The statement can never be true and hence 23 is not a solution.
3) 
Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.
The above statement is always true and hence 24 is a solution.
4) 
The fractions can no further be reduced.
The statement can never be true and hence 25 is not a solution.
