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3 years ago

Collect like termsd+ d +d

Mathematics

2 answers:

kari74 [83]3 years ago

4 0

Answer:

$d + d + d \: \: is \: \: a \: \: like \: \: term$

anastassius [24]3 years ago

4 0

Answer:

Step-by-step explanation:

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Write 17/25 as a decimal. A) 0.068 B) 0.68 C) 1.471 D) 6.8

ikadub [295]

I think it is D) 6.8

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4 years ago

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Interest calculated on a balance every three months is said to be compounded quarterly.

Mariulka [41]

Answer:

True

Step-by-step explanation:

The year is typically divided into equal different lengths of time. There are, for example, quarters, which divide the year by 4, i. e., in 4 periods of 3 months each. Other example are semesters, in this case, the year is divided into 2 periods of 6 months each. Taking this into account, an interest calculated on a balance every three months is compounded quarterly.

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3 years ago

Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. Which shows the correct substitution of the

posledela

Formulas, answers and solutions are in the file.

x= (2 +- 4)/2

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3 years ago

Find the value of x to the nearest tenth. *

Alla [95]

Answer:

x ≈ 61.8

Step-by-step explanation:

Using the sine ratio in the right triangle

sin15° = $\frac{opposite}{hypotenuse}$ = $\frac{16}{x}$ ( multiply both sides by x )

x × sin15° = 16 ( divide both sides by sin15° )

x = $\frac{16}{sin15}$ ≈ 61.8 ( to the nearest tenth )

8 0

4 years ago

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$

$\text{The length of the longer diagonal}=4+9.54$

$\text{The length of the longer diagonal}=13.54$

Therefore, the length of longer diagonal is approximately 13.54 inches.

3 0

3 years ago

Collect like termsd+ d +d​

Collect like termsd+ d +d