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Alik [6]
3 years ago
5

What is the place of the 9 in the number 5,948,003

Mathematics
2 answers:
tino4ka555 [31]3 years ago
4 0
The 9 is in the one hundred thousand's place
fomenos3 years ago
4 0
The place of the 9 in the number 5,948,003 is hundred thousands.
Hope this helps!! :D
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Cscθ - sinθ = _____
galina1969 [7]
So you maybe know that \csc x = \frac{1}{\sin x}. Now let us try to simplify the expression

\csc x - \sin x = \frac{1}{\sin x} - \sin x = \frac{1}{\sin x} - \frac{\sin^2 x }{\sin x}=\frac{1-\sin^2 x}{\sin x} =

= \frac{\cos^2 x}{\sin x} = \cot x \cdot \cos x
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3 years ago
Find a common denominator for 1/3 and 1/12 by dividing each whole into the same ​
Genrish500 [490]
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5 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 23 in. by 13 in. by
faltersainse [42]

Answer:

The dimension of the box is 17.66 in by 7.66 in by 2.67 in.

Therefore the volume of the box is 361.19 in^3.

Step-by-step explanation:

Given that the dimensions of a cardboard is 23 in by 13 in.

Let the side of the square be x in.

Then the length of the box= (23-2x) in

and the width of the box =(13-2x) in

and height = x in.

The volume of the box is = length ×width × height

                                         =[(23-2x)(13-2x)x] in^3

                                         =(299x-72x² +4x^3) in^3

∴V=299x-72x² +4x³

Differentiating with respect x

V'= 299-144x+12x²

Again differentiating with respect x

V''= -144+24x

To find the dimensions, we set V'=0

∴299-144x+12x²=0

Applying Sridharacharya formula that is the solution of a quadratic equation ax²+bx+c is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Here a=12, b=-144 , c=299

\therefore x=\frac{-(-144)\pm\sqrt{(-144)^2-4.12.299}}{2.12}

\Rightarrow x= 9.33, 2.67

If  we take x=9.33 in, then the width of the box [13-(2×9.33)] will negative.

∴x = 2.67 in

If at x = 2.67, V''<0 , then the volume of the box will be maximum or V''>0 then volume of the box will be minimum.

V''|_{x=2.67}=-144+(24\times 2.67)=-79.92

Therefore  at x = 2.67, the volume of the box maximum.

The length of the box =[23-(2×2.67)] in

                                    =17.66 in

The width of the box =[13-(2×2.67)] in

                                  =7.66 in

The height of the box= 2.67 in

The dimension of the box is 17.66 in by 7.66 in by 2.67 in.

Therefore the volume of the box is =(17.66×7.66×2.67) in^3

                                                            =361.19 in^3

8 0
3 years ago
We need a minimum of 30 book sales by today. If 10 books were sold yesterday, what are the possible numbers for sales today
amm1812

I mean it would be A and D because I don't know why they are both the same answer. If 10 books were sold yesterday, at LEAST 20 are needed to make the goal.

6 0
3 years ago
Dale has a special deck of cards. Each card has a different rational number on it. The cards are 0.25, 4/5, 2/9, 0.48, and 8/11.
Mila [183]

Answer:

explain this question more clearer pls

Step-by-step explanation:

7 0
3 years ago
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