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Gnesinka [82]
2 years ago
6

10.Admission to the Carnival is $4. Each game played costs an additional $2.

Mathematics
2 answers:
Maksim231197 [3]2 years ago
6 0

Answer:

y = 4 + 2x

Step-by-step explanation:

Marianna [84]2 years ago
3 0

Answer:

here u go:)

Step-by-step explanation:

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Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9
mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that \mu = 20.5, \sigma = 0.9

What percentage of full-term babies are between 19 and 21 inches long at birth?

The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then

X = 21

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.5}{0.9}

Z = 0.56

Z = 0.56 has a p-value of 0.7123

X = 19

Z = \frac{X - \mu}{\sigma}

Z = \frac{19 - 20.5}{0.9}

Z = -1.67

Z = -1.67 has a p-value of 0.0475

0.7123 - 0.0475 = 0.6648

0.6648*100% = 66.48%

66.48% of full-term babies are between 19 and 21 inches long at birth

5 0
2 years ago
Your favorite baseball player is doing much better this year than he did last year. Last year he got 5656 hits. This year he has
Lostsunrise [7]
I believe the answer is 186,648.
6 0
3 years ago
Read 2 more answers
Consider the figure below. Abraham cut regular pentagon ABCDE into quadrilateral BEGC. Which of the following statements is true
Genrish500 [490]

Let 'n' be the number of side of a regular polygon each angle are equal and sum of  each angle equal to (n-2)×180. \\∴For a regular pentagon have five equal side, n=5\\ ∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108° \\ Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio \\ Therefore ∠ABE : ∠CBE = 36: 72\\∴ ∠GCB + ∠CBE = 108° +72°=180°

5 0
3 years ago
Read 2 more answers
If r = 4 and ^a8 = 100, what is the first term of the geometric<br> sequence?
telo118 [61]

The first term of the geometric  sequence is 0.0061

<u>Step-by-step explanation:</u>

The general form of geometric  sequence is a, ar, ar²,ar³,.......

where,

  • a is the first term of the sequence.
  • r is the common ratio. Here, the common ratio r = 4.
  • The 8th term of the sequence is 100. Hence n = 8.

<u>The formula to find the nth term of the geometric sequence is given by :</u>

⇒ n_{th} term = ar^{n-1}

⇒ 8_{th}term  = a\times4^{8-1}

⇒ 100 = a \times 4^{7}

⇒ 100 = a \times 16384

⇒ a = \frac{100}{16384}

⇒ a = 0.0061

Therefore, the first term of the geometric  sequence is 0.0061

6 0
3 years ago
Explain how to find the estimated sum of <br><br><br> 5<br> 8<br> +<br> 2<br> 9<br> .
mina [271]

The estimated sum of the numbers fifty-eight (58) and twenty-nine (29) is equal to ninety (90).

<h3>What is the difference between a regular sum and an estimated sum?</h3>

In an estimated sum, the numbers are rounded; on the other hand, in a regular sum, the numbers are not changed.

<h3>What is the estimated sum of 58 and 29?</h3>

1. Round the numbers:

  • 58 = 60 as this number is nearest to 60 than to 58.
  • 29= 30 because of the same reason explained above.

2. Add the rounded numbers:

  • 60 + 30 = 90

Learn more about estimated sum in: brainly.com/question/660898

#SPJ1

7 0
2 years ago
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