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Gnesinka [82]
2 years ago
6

10.Admission to the Carnival is $4. Each game played costs an additional $2.

Mathematics
2 answers:
Maksim231197 [3]2 years ago
6 0

Answer:

y = 4 + 2x

Step-by-step explanation:

Marianna [84]2 years ago
3 0

Answer:

here u go:)

Step-by-step explanation:

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maksim [4K]
Lo siento, no hablo español
8 0
3 years ago
under a dilation, the point (2,6) is moved to (6,18) what is the scale factor of the dilation? enter your answer in the box​
Anestetic [448]
<h2>3</h2>

Step-by-step explanation:

The equation of line passing through the two points is \frac{y-y_{1} }{x-x_{1} }=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}

When substituted,the equation becomes \frac{y-6}{x-2}=\frac{18-6}{6-2}

which when simplified is y=3\times x

The line clearly passes through origin.

The distance between two points is \sqrt{(y_{1}-y_{2} )^{2}+(x_{1}- x_{2} )^{2}}

Distance between origin and (2,6) is \sqrt{40}.

Distance between origin and (6,18) is \sqrt{360}

Scale factor is  \frac{distance\text{ }of\text{ }p_{2}\text{ from origin}}{distance \text{ } of \text{ } p_{1}\text{ from origin}}

So,scale factor is \frac{\sqrt{360} }{\sqrt{40} }

which when simplified becomes 3.

6 0
2 years ago
The enrollment for a new program is 1,500 students. the program is expected to grow at a rate of 0.03. what is the expected enro
Hatshy [7]

The expected enrolment in 7 years is  1845.

<h3>What is the expected enrolment?
</h3>

The formula for calculating future value of the number of students is an exponential equation with this form:

FV = P (1 + r) ^n

  • FV = Future population
  • P = Present population
  • R = rate of growth of the population
  • N = number of years

1500 x (1.03)^7 = 1845

To learn more about future value, please check: brainly.com/question/18760477

#SPJ1

3 0
2 years ago
The graph of y=sin is stretched vertically by a factor of 3 , compressed horizontally by a factor of 6 (angular frequency of 6),
SVEN [57.7K]

Answer:

uhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
What is the radius of a circle with the equation x^2+y^2+6x-2y+3?
atroni [7]

Answer:

r = √13

Step-by-step explanation:

Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms:  x^2 + 6x            + y^2 -2y             = 3.  Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."  

We need to "complete the square" of x^2 + 6x.  I'll just jump in and do it:  Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x:     x^2 + 6x  + 3^2 - 3^2.  Then do the same for y^2 - 2y:  y^2 - 2y + 1^2 - 1^2.

Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2.  Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1.  Making these replacements:

(x + 3)^2 - 9 + (y - 1)^2 -1 = 3.  Move the constants -9 and -1 to the other side of the equation:  (x + 3)^2 + (y - 1)^2 = 3 + 9 + 1 = 13

Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r:  r^2 = 13, so that the radius is r = √13.


8 0
2 years ago
Read 2 more answers
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