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aleksklad [387]
3 years ago
15

Find the square root of each.

Mathematics
1 answer:
DIA [1.3K]3 years ago
8 0
169=13
144=12
Hope this helps and please give brainliest!
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How do we post a picture?
svet-max [94.6K]

Answer:

click on the thing that looks like a paper clip and pick the pic u wanna post

Step-by-step explanation:

3 0
3 years ago
Joseph wants to line his garden with a fence that cost $2.25 per foot. The length of the garden is 6 yards and the width is 2.5
Galina-37 [17]

Answer:

$38.25

Step-by-step explanation:

Perimeter of a rectangle = 2W + 2L

(where W is the width and L is the length)

Given:

  • width = 2.5 yd
  • length = 6 yd

⇒ perimeter = (2 x 2.5) + (2 x 6)

                     = 5 + 12

                     = 17 yd

Given:

  • cost of fence = $2.25 per foot

⇒ total cost = 17 x 2.25

                    = $38.25

7 0
3 years ago
Read 2 more answers
SOMEONE HELP FAST THIS IS DUE SOON PLZ
nordsb [41]

Answer:

-27.5

Step-by-step explanation:

4 0
3 years ago
A rectangle has a height of 3p2+1 and a width of p3+4 your answer should be a polynomial in standard form
drek231 [11]

Answer:

3p^5+p^3+12p^2+4

Step-by-step explanation:

5 0
3 years ago
Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
3 years ago
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