2 years ago

Jacob opened a money-market account. In the first month, he made an initial deposit of $500, and

Mathematics

1 answer:

natima [27]2 years ago

6 0

Answer:

after 13 months

Step-by-step explanation:

........ur welcome..........

1475-500=975

975÷75=13

so 13 months

You might be interested in

Karen has 2 potatoes and she and she smashed one on your head how many does she have now

Tatiana [17]

One potato...at least i think so

6 0

2 years ago

PJ will begin her cake deliveries at 12:20 . She asked to remind her 30 minutes before she has to leave. What time should I remi

mojhsa [17]

Answer:

At 11:50

Step-by-step explanation:

1. Subtract the hours and the minutes separately

12: 20

- 0: 30

12: -10

2. If the minutes are negative, subtract 1 from the hours and add 60 to the minutes.

12: -10

- 1: + 60

11: 50

You should remind PJ about her deliveries at 11:50.

4 0

2 years ago

Identify the coefficient(s) of the variable in the expression below.

tankabanditka [31]

Answer:

Step-by-step explanation:

25 and 6

Coefficient is the number in front of the unknown variable

3 0

2 years ago

Read 2 more answers

What is the mode of this set of data? 1982 1988 1989 1994 1995 2005

Cerrena [4.2K]

All of the numbers are the mode, so it is
1982, 1988, 1989, 1994, 1995, 2005

8 0

2 years ago

Read 2 more answers

Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000

zvonat [6]

Answer:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

$A = \int\limits^t_ {1} \,{13\cdot x^{3}} dx$

$A = 13 \int\limits^t_1 {x^{3}} \, dx$

$A = \frac{13}{4}\cdot (t^{4}-1)$

Evaluated areas are presented below:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

8 0

3 years ago