There are four aces, 12 face cards and 4 7s in a standard 52 card deck. The probability of getting an ace on the first draw is 4/52 or 1/13. For the second draw there are now 51 cards in the deck (assuming the draws are without replacement), so the probability of getting a face card is 12/51. Given an ace and a face card on the first two draws, the probability of a 7 on the third draw is 4/50 or 2/25. The probability of getting all three is 1/13*12/51*2/25.
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Answer:
the answer would be 1/15, or approximately 0.067.
Step-by-step explanation:
Answer:
2*2*3*5
Step-by-step explanation:
We need to factor 60 until it is prime numbers
60 = 12*5 5 is prime 12 is not
=3*4 *5 3,5 prime 4 is not
= 3 *2*2 *5 2,3,5 are prime
Rearranging the order
=2*2*3*5
Answer:
If your answer is linear, I would suggests: 1,2,4 maybe there's another one but I'm confident about those though. Hopefully I helped you with my options.
Step-by-step explanation:
Answer:
12 teams
Step-by-step explanation:
We know that 38 players can fit into 4 groups, 8 times ...
32 divide 8 = 4
We have the number with 96, and we need to find the groups
we do the same as done with the first one...
because 32 divided by 8 is 4
we do
96 divide 8 = 12
aswell
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<em>hope this helped : )</em></u></h2>