Answer:
i believe its x= 16
Step-by-step explanation:
(4/2) 2x/4 = 8/1 (4/2)
after you do that it should be
x = 32/2, now just simplify
x=16
Step 1) simplify the constants, so basically you are doing the 3-4 part and turning the equation in -8x-1>-1
Step 2) isolate the variable, first you need to add 1 to both sides to cancel it off then the equation is -8x>0. Next you divide both sides by -8, don't forget that when you multiply or divide by a negative you need to flip the sign which makes the equation x<0 because when you divide 0 by any number it is still 0
Hope this helped!
Answer: x<0
I think it’s the third one’s
A+5 = 1 side, so the perimeter is 3(a+5) or P = 3a+15
9514 1404 393
Answer:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
142 fish
Step-by-step explanation:
A) The differential equation is modified by adding a -50 fish per year constant term:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
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B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.
(0.4/1200)(N)(1200-N) -50 = 0
N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient
N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square
(N -600)^2 = 210,000 . . . . . simplify
N = 600 + √210,000 ≈ 1058
This steady-state number of fish is ...
1200 - 1058 = 142 . . . . below the original carrying capacity
