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Debora [2.8K]
3 years ago
9

Uranus is 19.2 AU. How many miles apart is Uranus from the Sun?

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
3 0

Answer:

Uranus distance from the sun is 1.79 billion miles.

Hope it helps :)

Step-by-step explanation:

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Consider the expression 17x+8x+35.Which of these mathematical statements could be used to accurately describe the given expressi
Mrac [35]
3. The product of seventeen and a number, increased by the product of eight and the same number, increased by thirty/five.
4. Seventeen times a number plus eight times the same number plus thirty five
5 0
3 years ago
Need Help Please I'm Out Of Time ;(
Grace [21]

Answer:

(-1, 7)

Step-by-step explanation:

Since five units away from (-1,2), you add five on both variables of the coordinate.

Vertical transition:

(-1 + 5, 2)

(4,2)

Horizontal transition:

(-1, 2 + 5)

(-1, 7)

Vertical and horizontal transition:

(4, 7)

Out of all the option, (-1, 7) is the viable option.

8 0
3 years ago
4 more than twice a number
Nataliya [291]
Twice means two times something so2a. Four more than means adding for so your answer is 2a+4
7 0
3 years ago
Two cars left the city for a suburb, 120 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the
Virty [35]

Answer:

V1 = 60 km/h

V2 = 40 Km/h

Step-by-step explanation:

The speed of an object is defined as

Speed =  distance / time

Let

V1 be the speed of the faster car

V2 be the speed of the other car

t1 the time it took for the first car to arrive

t2 the time it took for the second car to arrive

d1 the distance traveled by first car

d2 the distance traveled by second car

We know thanks to the problem that

V1 = V2 + 20 Km/h

t1 = t2 - 1 hour

d1 = d2 = 120 Km

d1 = V1 * t1

d2 = V2* t2

V1 * t1 = V2* t2

V1* t1 = (V1 -20)*(t1 +1)

The system of equations

(V1 -20)*(t1 +1) = 120

V1 * t1 = 120

120 + (120/t1) -20*t1 = 140

(120/t1) -20*t1  = 20

Which gives,

t1 = 2

This means

V1 = 60 km/h

V2 = V1 - 20 Km/h =  40 Km/h

6 0
3 years ago
A party rental company has chairs and tables for rent. The total cost to rent
Paha777 [63]

Let c= cost to rent each other

Let t= cost to rent each other

2c+3t=25

6T+5T=49

Multiply the 2nd equation by (-2) and add equation together  

2c+3t=25

-12c-10t= 98

2t=98

T=49

Put this value into the 1st equation solve c

2c+3(49)=49

2c+147=49

2c=98

C=49

Cost to each chair and table are same 49.


4 0
3 years ago
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