Answer:
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Step-by-step explanation:
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Answer: The right hand limit is 4
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Start on the right side of the value x = 2. In other words, start at some value larger than 2, say x = 4. Starting at x = 4, move closer to x = 2. Move as close as you can. The closer x gets to 2, the closer y gets to 4. You'll never actually get to x = 2 or y = 4 because of the hole. However, the right-hand limiting value is 4 assuming you can keep getting closer and closer.
Note: if you approach x = 2 from the left side, you arrive at a different y value So this suggests that overall, the limit at x = 2 doesn't exist. But the right hand limit (RHL) does exist as described above.
3(2x+2)=3x-15
mutiply the bracket by 3
(3)(2x)(3)(2)= 6x+6
6x+6= 3x-15
move 3x to the other side
sign changes from +3x to -3x
6x-3x+6= 3x-3x-15
6x-3x+6= -15
3x+6= -15
move +6 to the other side
sign changes from +6 to -6
3x+6-6= -15-6
3x= -21
divide by 3 for both sides
3x/3= -21/3
x= -7
Answer: x= -7
