Answer: She went
times during the summer.
Step-by-step explanation:
If Louisa's savings change by
each time she goes bowling and it went to
, that means that Louisa went another
times.

So therefore your answer would be 11.
n>-6 and n<3 (there's your answer my friend)
If Jimmy's new cell cost him $49.99 with a 75% discount, then $49.99 is <span>100%−75%=25%</span><span> of the original price.
</span>
The original price of the cell phone was <span>$199.96</span><span>.</span>
Answer:
P(Y ≥ 15) = 0.763
Step-by-step explanation:
Given that:
Mean =135
standard deviation = 12
sample size n = 50
sample mean
= 140
Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses
Then,

The probability that X is greater than 140 is :
P(X>140) = 1 - P(X ≤ 140)



From z tables,


Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140
Then;


∴
P(Y ≥ 15) = 1- P(Y< 15)
P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

P(Y ≥ 15) = 0.763
Answer:
The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try!
Step-by-step explanation: