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3 years ago

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)

Mathematics

1 answer:

White raven [17]3 years ago

6 0

Answer:

$\boxed{-2; 6}$

Step-by-step explanation:

Think of this as an ordinary addition problem.

What must you add to 3a³ to get 1a³? Answer: add -2a³

3 + (-2) = 1

What must you add to -5b³ to get 1b³? Answer: add 6b³

-5 + 6 = 1

Then, the addition looks like this:

$\begin{array}{rcr}3a^{3} & + & -5b^{3}\\\boxed{-2}a^{3} & + & \boxed{6}b^{3}\\a^{3} & + & b^{3\\\end{array}$

The numbers in the boxes are -2 and 6.

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The 98% of the confidence interval for the true average salary of Knirhsdaeh employees as a psychology counselor

(75.4206, 86.5794)

Step-by-step explanation:

Step(i):-

Given that the mean of the sample = $81 k

Given that the size of the sample 'n' = 23

Given that the standard deviation for the salaries is $13 k

Step(ii):-

98% of the confidence interval for the true average salary of Knirhsdaeh employees is determined by

 $(x^{-} - t_{0.02} \frac{S.D}{\sqrt{n} } , x^{-} + t_{0.02} \frac{S.D}{\sqrt{n} })$ 

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3 years ago

Three times the sum of 5 and a number is a value between 12 and 21.

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Answer:

Step-by-step explanation:

We are told that three that the sum of 5 and a number is between 12 and 21 which means:

$12$

Divide all sides by 3:

$\frac{12}{3}$

$4$

Subtract 5 on both sides:

$4-5$

Simplify:

$-1$

So the answer is A.

Slightly different route:

$12$

Distribute 3 to the terms in the ( ) next to it:

$12$

Subtract all sides by 15:

$12-15$

Simplify:

$-3$

Divide both sides by 3:

$\frac{-3}{3}$

Simplify:

$-1$

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3 years ago

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)​

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)