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3 years ago

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)

Mathematics

1 answer:

White raven [17]3 years ago

6 0

Answer:

$\boxed{-2; 6}$

Step-by-step explanation:

Think of this as an ordinary addition problem.

What must you add to 3a³ to get 1a³? Answer: add -2a³

3 + (-2) = 1

What must you add to -5b³ to get 1b³? Answer: add 6b³

-5 + 6 = 1

Then, the addition looks like this:

$\begin{array}{rcr}3a^{3} & + & -5b^{3}\\\boxed{-2}a^{3} & + & \boxed{6}b^{3}\\a^{3} & + & b^{3\\\end{array}$

The numbers in the boxes are -2 and 6.

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Answer:

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Step-by-step explanation:

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1 year ago

Read 2 more answers

Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0

3 years ago

Which one of these polls is the correct answer? Please help.

professor190 [17]

M= 4

Hope that helps have a great day!

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2 years ago

Jake map shows the distance from the big star coffee to the restaurant supply store as it 3 cm is the scale of the map is 1 cm t

kumpel [21]

Answer: The real distance from the shop to the store = 24 km.

Step-by-step explanation:

Given: The distance from the big star coffee to the restaurant supply store = 3cm (On map)

Scale of the map : 1 cm to 8 km

That means, the real distance from the shop to the store = 3 x ( 8 km ) = 24 km

Hence, the real distance from the shop to the store = 24 km.

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3 years ago

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crimeas [40]

Answer:

r^2=(A/pi)

Step-by-step explanation:

if A=pi*r^2 then maybe dividing by pi to get r^2 alone says r^2=(A/pi) or to get rid of the exponent you may square root each side so r=(sqrt(A/pi))

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3 years ago

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)​

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)