Ask question

Ask question

All categories

Mekhanik [1.2K]

3 years ago

8

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)

1 answer:

White raven [17]3 years ago

6 0

Answer:

$\boxed{-2; 6}$

Step-by-step explanation:

Think of this as an ordinary addition problem.

What must you add to 3a³ to get 1a³? Answer: add -2a³

3 + (-2) = 1

What must you add to -5b³ to get 1b³? Answer: add 6b³

-5 + 6 = 1

Then, the addition looks like this:

$\begin{array}{rcr}3a^{3} & + & -5b^{3}\\\boxed{-2}a^{3} & + & \boxed{6}b^{3}\\a^{3} & + & b^{3\\\end{array}$

The numbers in the boxes are -2 and 6.

You might be interested in

How many sides is a decagon? I forgot LOL

umka21 [38]

Answer:

10 sides.

Step-by-step explanation:

In geometry, a decagon is a ten-sided polygon or 10-gon. The total sum of the interior angles of a simple decagon is 1440°. A self-intersecting regular decagon is known as a decagram.

3 0

3 years ago

Yeah i need help someone lol

SIZIF [17.4K]

Answer:

45%

Step-by-step explanation:

If it not right im sorry that is a very odd question

3 0

3 years ago

The midpoint of ab is M (-6,1 ). if the coordinates of A are (-7,-3 ),what are the coordinates of B

Scrat [10]

Answer:

B(-5,5).

Step-by-step explanation:

It is given that midpoint of AB is M (-6,1).

Coordinates of A are (-7,-3 ).

We need to find the coordinates of point B.

Let coordinates of point B are (a,b).

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

Midpoint of AB is

$Midpoint=\left(\dfrac{-7+a}{2},\dfrac{-3+b}{2}\right)$

$(-6,1)=\left(\dfrac{-7+a}{2},\dfrac{-3+b}{2}\right)$

On comparing both sides, we get

$\dfrac{-7+a}{2}=-6$

$-7+a=-12$

$a=-12+7$

$a=-5$

$\dfrac{-3+b}{2}=1$

$-3+b=2$

$b=2+3$

$b=5$

Therefore, the coordinates of B are (-5,5).

6 0

4 years ago

Jordan gets paid to mow his neighbor's lawn. For every week that he mows the lawn, he earns $20. What is the rule as an algebrai

lilavasa [31]

$We\ can\ write\ it\ as\ a\ function:\\y=20x\\\\x-number\ of\ weeks\\y-earnings\\Earnings\ depands\ on\ number\ of\ weeks.$

6 0

3 years ago

Charlie reads quickly. He reads 1\dfrac371 7 3 1, start fraction, 3, divided by, 7, end fraction pages every \dfrac23 3 2 st

OLEGan [10]

<h2>Answer:</h2>

The number of pages he will read in one minute is:

$2\dfrac{1}{7}\ \text{pages}$

<h2>Step-by-step explanation:</h2>

It is given that:

Charlie reads $1\dfrac{3}{7}\ \text{pages}$ in every $\dfrac{2}{3}\ \text{minutes}$ .

We know that:

$1\dfrac{3}{7}=\dfrac{10}{7}$

This means that:

Charlie reads $\dfrac{10}{7}\ \text{pages}$ in every $\dfrac{2}{3}\ \text{minutes}$ .

This means that:

$\text{In}\ \dfrac{2}{3}\ \text{minutes he reads}\ \dfrac{10}{7}\ \text{pages}\\\\\text{Hence}$

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{\dfrac{10}{7}}{\dfrac{2}{3}}\ \text{pages}$

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{10\times 3}{7\times 2}\ \text{pages}$

Hence,

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}$

Hence,

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}$

$\text{In}\ 1\ \text{minute he will read}\ 2\dfrac{1}{7}\ \text{pages}$

4 0

3 years ago

Read 2 more answers