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3 years ago

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)

Mathematics

1 answer:

White raven [17]3 years ago

6 0

Answer:

$\boxed{-2; 6}$

Step-by-step explanation:

Think of this as an ordinary addition problem.

What must you add to 3a³ to get 1a³? Answer: add -2a³

3 + (-2) = 1

What must you add to -5b³ to get 1b³? Answer: add 6b³

-5 + 6 = 1

Then, the addition looks like this:

$\begin{array}{rcr}3a^{3} & + & -5b^{3}\\\boxed{-2}a^{3} & + & \boxed{6}b^{3}\\a^{3} & + & b^{3\\\end{array}$

The numbers in the boxes are -2 and 6.

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3 years ago

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marusya05 [52]

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3 years ago

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3 years ago

What is the value of k in the equation k/3 - 5 = 34? 11 1/3 13 102 117

mestny [16]

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3 years ago

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"Each week, a subcommittee of four individuals is formed from among the members of a committee comprising seven individuals. Two

denis-greek [22]

Answer:

140 weeks.

Step-by-step explanation:

We are being asked for the maximum number that can elapse without having 2 subcommitees with the same members and the same chair. Notice that the secretary is not mentioned in this statement, so we can ignore that position.

Now, the maximum number of weeks would be equal to the total possible combinations of subcommitees that can be formed from the 7 individuals commiteed, times the number of options that can sit at the chair possition.

The total possible combinations of subcommitees that can be formed from the 7 individuals can be expressed like the following expression. Notice that there is no a particular order to be considered, so we use the combination formula:

$\left[\begin{array}{ccc}7\\4\end{array}\right]$ = $\frac{7!}{4!(7-4)!}$ = 35

Now, each of the 4 individuals have the same probability of being chosen as the chair commitee. So, we have to multiply 4 times the number of possible subcommitees in order to arrive our answer:

x = 35 * 4 = 140

This would be the maximum number of subcommitees that can be formed with no subcommitees with the same members and the same chair occurring.

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3 years ago

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)​

(3a³ - 5b³) + ? a³+ ? b³ =(a³+b³)