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postnew [5]
2 years ago
10

One pipe can fill a pool in 9 hours. Another pipe can fill the pool in 6 hours. How long would it take them to fill the pool if

they were working together?

Mathematics
1 answer:
kow [346]2 years ago
3 0

Answer:

3.6 hours or 3 hours and 36 minutes.

Step-by-step explanation:

If the first pipe can fill the pool in 9 hours that means that in 1 hour it fills \frac{1}{9} of the pool, we use the same logic for the second pipe and conclude that in 1 hour it feels up \frac{1}{6} of the pool. If both were to fill the pool together that means that in 1 hour they would fill...

\frac{1}{9} +\frac{1}{6} = \frac{5}{18} of the pool in 1 hour.

Now to find how many hours it will take divide the pool by the speed with which it is getting filled.

1 / \frac{5}{18} = 3.6 hours

3.6 hours in other words is 3 hours and 36 minutes.

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