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ehidna [41]
3 years ago
10

Find the value of 17 33 rounded to the nearest ten-thousandth.

Mathematics
1 answer:
alexira [117]3 years ago
7 0

Answer:

0.5152

Step-by-step explanation:

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Complete the comparison: 3 + 7 > ? A. 8 + 2 B. 10 − 2 C. 7 + 3 D. 9 + 4
Dafna1 [17]
3 + 7 > 10 - 2
10 > 8...correct
5 0
3 years ago
PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSWER
Semenov [28]
= 9 * 10^5 * 3 * 10^10

= 27 * 10^5 * 10^10

= 27 * 10^15

= 2.7 * 10^16 - The best selection appears to be the first option.

Good luck :)
4 0
3 years ago
-2x+5-40-9x - 13 help me please​
Naddika [18.5K]

Answer:

-48/11

Step-by-step explanation:

-2x+5-40-9x-13=0

-11x=40-5+13

-11x=48

x=-48/11

7 0
4 years ago
A marathon is 26.2 miles. What is the least number of times Miguel must run for his total distance run during training to exceed
ziro4ka [17]

Missing part of the question

Miguel has started training for a race. The first time he trains, he runs 0.5 mile. Each subsequent time he trains, he runs 0.2 mile farther than he did the previous time.

What is the arithmetic series that represents the total distance Miguel has run after he has trained n times?

Answer:

The least number of times Miguel must run for his total distance run during training to exceed the distance of a marathon is 17.3 miles

Step-by-step explanation:.

Given parameters

Miguel first run = 0.5 mile

Subsequent run = 0.2 mile

This question is an arithmetic progression.

We'll make use of arithmetic progression formula to solve this

Formula:.

Tn = a + (n - 1)d

Where a = first term

n = number of terms

d = common difference

In this case

a = first run = 0.5 mile

d = subsequent run = 0.2 mile

So, Tn = a + (n - 1)d become

Tn = 0.5 + (n - 1) 0.2

Tn = 0.5 + 0.2n - 0.2

Tn = 0.5 - 0.2 + 0.2n

Tn = 0.3 + 0.2n

The arithmetic series of an arithmetic progression is calculated using

Sn = ½(a + Tn) * n

By substituton, we have

Sn = ½(0.5 + 0.3 + 0.2n) * n

Sn = ½(0.8 + 0.2n) * n

Sn = 0.4n + 0.1n²

b.

Since the race is 26.2 miles then the least number of times is given as

Sn ≥ 26

0.4n + 0.1n² ≥ 26.2

0.1n² + 0.4n - 26.2 ≥ 0

Using quadratic formula

n = (-b ± √(b² - 4ac))/2a

Where b = 0.4 a = 0.1 and C = -26.2

So,

n = -0.4 ± √(0.4² - 4 * 0.1 * ,26.2)/2 * 0.1

n = (-0.4 ± √10.64)/0.2

n = (0.4 ± 3.26)/0.2

n = (0.4 + 3.26)/0.2 or (0.4 - 3.26)/0.2

n = 3.46/0.2 or -2.86/0.2

n = 17.3 or -14.3

Since n can't be negative

n = 17.3 miles

The least number of times Miguel must run for his total distance run during training to exceed the distance of a marathon is 17.3 miles

7 0
3 years ago
Read 2 more answers
Determine the possible number of positive real zeros and negative real zeros for each polynomial function given by Descartes rul
snow_tiger [21]

Answer:

there are going to be 4 real zeros

Step-by-step explanation:


8 0
3 years ago
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