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nexus9112 [7]
3 years ago
6

Langston has $45$ greeting cards. He gives $18$ of the cards to his friends. What percent of his greeting cards does he give to

his friends?
Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
5 0
27, subtract 45 and 18
dalvyx [7]3 years ago
3 0

Answer:

45-18=27 Greeting cards

Step-by-step explanation:

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PLEASE HELP ME PLEASE I NEED HELP AS FAST AS POSSIBLE
bearhunter [10]

Answer:

monomial

Step-by-step explanation:

because it has one variable which in this case is b and one number in this case is 10

6 0
3 years ago
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How do you turn 1/3 into a whole number
Luda [366]

Answer:

Step-by-step explanation:

There is no fractional or decimal part. And no negatives. 1/3 = 0.33333333 with 3 keep repeating. If you want to round it to the nearest whole number, it is 0

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3 years ago
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In the diagram, the radius of the outer circle is
JulijaS [17]

the value of x is 8 cm.

<u>Step-by-step explanation:</u>

Correct Question : In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded region is 220π cm2. What is the value of x? Enter your answer in the box.

We have ,

the area of a circle =  πr²

the outer circle area = \pi(2x)^2 =4\pi x^2

the inside circle area = \pi (6)^2= 36\pi

According to Question,

the outer circle area - the inside circle area = he shaded region

⇒ \pi (4x^2)-36\pi =220\pi

⇒ x^2-9 =55

⇒ x^2=64

⇒x =\sqrt{64}=8

Therefore , the value of x is 8 cm.

5 0
2 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

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The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
Complete the solution of the equation. Find the<br> value of y when x equals -14.<br> -2x + 5y = 8
shepuryov [24]

Answer:

y = -4

Step-by-step explanation:

-2x + 5y = 8

Let x=-14

-2(-14) +5y = 8

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Subtract 28 from each side

28-28 +5y = 8-28

5y = -20

Divide by 5

5y/5 = -20/5

y = -4

4 0
3 years ago
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