All categories

3 years ago

Use the drawing tool(s) to form the correct answers on the provided graph.

Mathematics

1 answer:

sukhopar [10]3 years ago

8 0

Answer:

h(x) is y , that's mean y is output or answer

x can be -1, 0 , 1

Step-by-step explanation:

I. replace x value

II. you'll find the answer

III. draw the answer to your software

You might be interested in

How do I do this? <br><br> help!!

kakasveta [241]

Answer:

...

Step-by-step explanation:

7 0

3 years ago

Which is greater 82\8 or 37\4.How do you know.extra answer 50 pt

ozzi

Divide both. 82/8=10.25 37/4=9.25 The first is greater.

4 0

4 years ago

A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$

$x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i$

The solutions are:

$x=3i,\:x=-3i$

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor $x^2+9$ :

First, multiply the constant in the polynomial by $i^2$ where $i^2$ is equal to -1.

$x^2+9i^2$

Since both terms are perfect squares, factor using the difference of squares formula

$a^2-i^2=(a+i)(a-i)$

$x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)$

5 0

3 years ago

How to use the break apart strategy to find 247+ 358 in words

r-ruslan [8.4K]

247 is equal to 200+40+7.

358 is equal to 300+50+8.

To find the answer, add 200+300=500.
40+50=90
7+8=15

500+90+15=605

The answer is 605.

5 0

3 years ago

Read 2 more answers

What are numbers that are either whole numbers or negatives of whole numbers

leonid [27]

These are called integer numbers.

We start with natural numbers (or whole numbers), i.e. the set

$\mathbb{N} = \{0,1,2,3,4,\ldots\}$

When you add the opposite of each whole number, you have the set of integers:

$\mathbb{Z} = \{0,\pm1,\pm2,\pm3,\ldots\}$

8 0

3 years ago

Read 2 more answers