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cluponka [151]
2 years ago
14

The left one pls help me

Mathematics
1 answer:
nirvana33 [79]2 years ago
5 0
The bear has 4 paws branilesg plzzzz
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Which ordered pair is a solution to the equation? y=x3/4
Leni [432]

Answer:

(8,6)

Step-by-step explanation:

y=x3/4

y=8(3/4)

y=24/4

y=6

when you input 8 for x, you get 6 for y.

6 0
3 years ago
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Someone pls help this is due in a bit
zhuklara [117]
The answer is 3.814 but if you wanna round to the nearest hundredth then it’s 3.81
7 0
3 years ago
A true-false question is to be posed to a husband and wife team. Both the husband and the wife will give the correct answer with
marysya [2.9K]

Answer:

Choose either strategy both are equally successful

Step-by-step explanation:

Given:-

- The probability of success for both husband (H) and wife (W) are:

                              P ( W ) = 0.8 , P ( H ) = 0.8

Find:-

- Which of the following is a better strategy for the couple?

Solution:-

Strategy 1

- First note that P ( W ) & P ( H ) are independent from one another, i.e the probability of giving correct answer of husband does not influences that of wife's.

- This strategy poses an event such that either wife knows the answer and answer it correctly or the husband knows and answers in correctly.

- We will assume that probability of either the husband or wife knowing the answer is 0.5 and the two events of knowing and answering correctly are independent. So,

                           P ( Wk ) = P (Hk) = 0.5

- The event P(S1) is:

                           P(S1) = P ( Hk & H ) + P ( Wk & W )

                           P(S1) = 0.5*0.8 + 0.5*0.8

                           P(S1) = 0.8

- Hence, the probability of success for strategy 1 is = 0.8

Strategy 2

- Both agree , then the common answer is selected otherwise, one of their answers is chosen at random.

- The success of strategy 2, will occur when both agree and are correct, wife is correct and answers while husband is not or husband is correct and he answers.

- The event P(S2) is:

                   P(S2) = P ( H & W ) + P ( H / W' & Hk ) + P ( H' / W & Wk )

                   P(S2) = P ( H & W ) + P ( H / W') P ( Hk ) + P ( H' / W) P (Wk)

                   P(S2) = P ( H & W ) + P ( H / W')*0.5  + P ( H' / W)*0.5

                   P(S2) = 0.5* [ P ( H & W ) + P ( H / W') ]  + 0.5* [ P ( H' / W) + P ( H & W )]

                   P(S2) = 0.5*P(H) + 0.5*P(W)

                   P(S2) = 0.5*0.8 + 0.5*0.8

                   P(S2) = 0.8

- Hence, the probability of success for strategy 2 is = 0.8

Both strategy give us the same probability of success.

                 

                       

4 0
3 years ago
Helpp!!!!! i will mark as brainliest !!<br><br>solve question i and ii ​
melomori [17]

Answer:

(i) Lowest Temperature: Warsaw

Highest Temperature: Cairo

(ii) 27.1 + 35.2 = 62.3°C

4 0
3 years ago
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You have 19 digs for your current volleyball season. There are 5 games left in the season. You want to break your previous recor
Charra [1.4K]

Answer:We must get more than 7 digs in the remaining 5 games  to break record of 26.


Step-by-step explanation:

Given situation:- Let  x represents the number of digs which we must get in the remaining 5 games to break your record ,and we have 19 digs for our current volleyball season.

To break  previous record of 26 digs in a season, we have to get more than 26 i.e. 19 digs added to x must be greater than 26

⇒x+19 ≥ 26

⇒x≥26-19⇒x≥7

Therefore,we must get more than 7 digs in the remaining 5 games  to break record of 26.


4 0
3 years ago
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