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anygoal [31]
3 years ago
6

It takes 40 minutes to fill a water tank, and 60 minutes to drain it. How many hours will it take to fill the tank while drainin

g it the entire time?
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0
I think this is a false question because when I fill up the bath tub, the faucet has more water poring out than the drainer. 
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What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
The sum of two polynomials is –yz2 - 322 – 4y + 4. If one of the polynomials is y - 4yz2 - 3, what is the other polynomial? 0 -2
JulsSmile [24]

Answer:

3yz² - 3z² - 5y + 7

Step-by-step explanation:

Sum of two polynomials = –yz² - 3z² – 4y + 4

One of the polynomial = y - 4yz²- 3

Find the other polynomial

The other polynomial = sum of the polynomials - one of the polynomial

= –yz² - 3z² – 4y + 4 - (y - 4yz² - 3)

= –yz² - 3z² – 4y + 4 - y + 4yz² + 3

= -yz² + 4yz² - 3z² - 4y - y + 4 + 3

= 3yz² - 3z² - 5y + 7

A. 0 -2yz?

B. – 4y + 7 01 - 2yz

C. – 3y + 1 0 -5yz² + 3z² – 3y + 1 D. 3yz² - 3z² – 5y + 7

6 0
3 years ago
a trader has 47,500 rupees with him. he placed an order for 22 items each costing rs. 1263. after making the payment for this pu
djverab [1.8K]

Answer:

since each item costs rs1263 we say

rs1263×22

27786

this means he spent rs27786

Her we now say rs47500-rs27786

=rs19714

This is to say that he has rs19714 left with him.

7 0
4 years ago
Read 2 more answers
Which function represents f(x)=3^x ?
Firdavs [7]

Answer:

The answer would be function 2.

Step-by-step explanation:

I found this out by plugging in 0 into x. What I got then was one. So I found that function 2 has a spot on 0, 1. that is how I got the answer.

Brainliest would be appreciated.

8 0
3 years ago
Read 2 more answers
Use &lt; , &gt; , = , ≤ , ≥ to complete these statements. 1) if x &lt; y , then y___ x, 2) if x &gt; 5 and 5 &gt; y, then x ___
vodomira [7]

Answer:

1) y > x

2) x > 5 > y

3) x ≤ 4  ( or 4 ≥ x )

4) x = y

Step-by-step explanation:

1) 1. y is greater than x

  2. so y > x

2) 1. 5 is less than x and more than y

   2. we can write this like x > 5 > y

   3. you can just squish them together as a shortcut usually: x > 5 and 5 > y      -->      x > 5 > y

3) 1. x is for at most, we can say this as x is less than or equal to 4

   2. this is written as x ≤ 4  or  4 ≥ x

4) 1. x - y = 0 so x and y must be the same value

   2. therefore x = y

4 0
3 years ago
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